matlab 解方程为何出现下面的情况啊 >> syms x y >> [y]=solve
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matlab 解方程为何出现下面的情况啊 >> syms x y >> [y]=solve
>> syms x y
>> [y]=solve('x^2*0.2+y^2*0.3=1')
y =
0.70710678118654752440084436210485*(10.0 - 3.0*y^2)^(1/2)
-0.70710678118654752440084436210485*(10.0 - 3.0*y^2)^(1/2)
谁帮我下面函数啊,解不了
[x0 y0 x1 y1 x2 y2]=solve('y1*a^2*(x1-x0)=x1*b^2*(y1-y0)','y2*c^2*(x2-x0)=x2*d^2*(y2-y0)','(y1-y0)^2+(x1-x0)^2=r^2','(y2-y0)^2+(x2-x0)^2=r^2','x1^2*b^2+y1^2*a^2=a^2*b^2','x2^2*d^2+y2^2*c^2=c^2*d^2','x0','y0','x1','y1','x2','y2')
>> syms x y
>> [y]=solve('x^2*0.2+y^2*0.3=1')
y =
0.70710678118654752440084436210485*(10.0 - 3.0*y^2)^(1/2)
-0.70710678118654752440084436210485*(10.0 - 3.0*y^2)^(1/2)
谁帮我下面函数啊,解不了
[x0 y0 x1 y1 x2 y2]=solve('y1*a^2*(x1-x0)=x1*b^2*(y1-y0)','y2*c^2*(x2-x0)=x2*d^2*(y2-y0)','(y1-y0)^2+(x1-x0)^2=r^2','(y2-y0)^2+(x2-x0)^2=r^2','x1^2*b^2+y1^2*a^2=a^2*b^2','x2^2*d^2+y2^2*c^2=c^2*d^2','x0','y0','x1','y1','x2','y2')
[x0 y0 x1 y1 x2 y2]=solve('y1*a^2*(x1-x0)=x1*b^2*(y1-y0)','y2*c^2*(x2-x0)=x2*d^2*(y2-y0)','(y1-y0)^2+(x1-x0)^2=r^2','(y2-y0)^2+(x2-x0)^2=r^2','x1^2*b^2+y1^2*a^2=a^2*b^2','x2^2*d^2+y2^2*c^2=c^2*d^2','x0','y0','x1','y1','x2','y2')
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