搜狗做题网利用日期、经纬度求日出日落时间 C语言程序代码
来源：学生作业帮 编辑：搜狗做题网作业帮 分类：综合作业 时间：2024/04/27 20:29:09
利用日期、经纬度求日出日落时间 C语言程序代码
急需单片机编程求任意一地日出日落时间,有写过这方面程序的求程序代码,给出代码后再给50分.
寻求C语言程序代码
急需单片机编程求任意一地日出日落时间,有写过这方面程序的求程序代码,给出代码后再给50分.
寻求C语言程序代码
#define PI 3.1415926
#include<math.h>
#include<iostream>
using namespace std;
int days_of_month_1[]={31,28,31,30,31,30,31,31,30,31,30,31};
int days_of_month_2[]={31,29,31,30,31,30,31,31,30,31,30,31};
long double h=-0.833;
//定义全局变量
void input_date(int c[]){
int i;
cout<<"Enter the date (form: 2009 03 10):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//输入日期
void input_glat(int c[]){
int i;
cout<<"Enter the degree of latitude(range: 0°- 60°,form: 40 40 40 (means 40°40′40″)):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//输入纬度
void input_glong(int c[]){
int i;
cout<<"Enter the degree of longitude(west is negativ,form: 40 40 40 (means 40°40′40″)):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//输入经度
int leap_year(int year){
if(((year%400==0) || (year%100!=0) && (year%4==0))) return 1;
else return 0;
}
//判断是否为闰年:若为闰年,返回1；若非闰年,返回0
int days(int year, int month, int date){
int i,a=0;
for(i=2000;i<year;i++){
if(leap_year(i)) a=a+366;
else a=a+365;
}
if(leap_year(year)){
for(i=0;i<month-1;i++){
a=a+days_of_month_2[i];
}
}
else {
for(i=0;i<month-1;i++){
a=a+days_of_month_1[i];
}
}
a=a+date;
return a;
}
//求从格林威治时间公元2000年1月1日到计算日天数days
long double t_century(int days, long double UTo){
return ((long double)days+UTo/360)/36525;
}
//求格林威治时间公元2000年1月1日到计算日的世纪数t
long double L_sun(long double t_century){
return (280.460+36000.770*t_century);
}
//求太阳的平黄径
long double G_sun(long double t_century){
return (357.528+35999.050*t_century);
}
//求太阳的平近点角
long double ecliptic_longitude(long double L_sun,long double G_sun){
return (L_sun+1.915*sin(G_sun*PI/180)+0.02*sin(2*G_sun*PI/180));
}
//求黄道经度
long double earth_tilt(long double t_century){
return (23.4393-0.0130*t_century);
}
//求地球倾角
long double sun_deviation(long double earth_tilt, long double ecliptic_longitude){
return (180/PI*asin(sin(PI/180*earth_tilt)*sin(PI/180*ecliptic_longitude)));
}
//求太阳偏差
long double GHA(long double UTo, long double G_sun, long double ecliptic_longitude){
return (UTo-180-1.915*sin(G_sun*PI/180)-0.02*sin(2*G_sun*PI/180)+2.466*sin(2*ecliptic_longitude*PI/180)-0.053*sin(4*ecliptic_longitude*PI/180));
}
//求格林威治时间的太阳时间角GHA
long double e(long double h, long double glat, long double sun_deviation){
return 180/PI*acos((sin(h*PI/180)-sin(glat*PI/180)*sin(sun_deviation*PI/180))/(cos(glat*PI/180)*cos(sun_deviation*PI/180)));
}
//求修正值e
long double UT_rise(long double UTo, long double GHA, long double glong, long double e){
return (UTo-(GHA+glong+e));
}
//求日出时间
long double UT_set(long double UTo, long double GHA, long double glong, long double e){
return (UTo-(GHA+glong-e));
}
//求日落时间
long double result_rise(long double UT, long double UTo, long double glong, long double glat, int year, int month, int date){
long double d;
if(UT>=UTo) d=UT-UTo;
else d=UTo-UT;
if(d>=0.1) {
UTo=UT;
UT=UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo))))));
result_rise(UT,UTo,glong,glat,year,month,date);
}
return UT;
}
//判断并返回结果（日出）
long double result_set(long double UT, long double UTo, long double glong, long double glat, int year, int month, int date){
long double d;
if(UT>=UTo) d=UT-UTo;
else d=UTo-UT;
if(d>=0.1){
UTo=UT;
UT=UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo))))));
result_set(UT,UTo,glong,glat,year,month,date);
}
return UT;
}
//判断并返回结果（日落）
int Zone(long double glong){
if(glong>=0) return (int)((int)(glong/15.0)+1);
else return (int)((int)(glong/15.0)-1);
}
//求时区
void output(long double rise, long double set, long double glong){
if((int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<10)
cout<<"The time at which the sun rises is "<<(int)(rise/15+Zone(glong))<<":0"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<" .\n";
else cout<<"The time at which the sun rises is "<<(int)(rise/15+Zone(glong))<<":"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<" .\n";
if((int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<10)
cout<<"The time at which the sun sets is "<<(int)(set/15+Zone(glong))<<": "<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<" .\n";
else cout<<"The time at which the sun sets is "<<(int)(set/15+Zone(glong))<<":"<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<" .\n";
}
//打印结果
int main(){
long double UTo=180.0;
int year,month,date;
long double glat,glong;
int c[3];
input_date(c);
year=c[0];
month=c[1];
date=c[2];
input_glat(c);
glat=c[0]+c[1]/60+c[2]/3600;
input_glong(c);
glong=c[0]+c[1]/60+c[2]/3600;
long double rise,set;
rise=result_rise(UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date);
set=result_set(UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date);
output(rise,set,glong);
system("pause");
return 0;
}\x09
#include<math.h>
#include<iostream>
using namespace std;
int days_of_month_1[]={31,28,31,30,31,30,31,31,30,31,30,31};
int days_of_month_2[]={31,29,31,30,31,30,31,31,30,31,30,31};
long double h=-0.833;
//定义全局变量
void input_date(int c[]){
int i;
cout<<"Enter the date (form: 2009 03 10):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//输入日期
void input_glat(int c[]){
int i;
cout<<"Enter the degree of latitude(range: 0°- 60°,form: 40 40 40 (means 40°40′40″)):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//输入纬度
void input_glong(int c[]){
int i;
cout<<"Enter the degree of longitude(west is negativ,form: 40 40 40 (means 40°40′40″)):"<<endl;
for(i=0;i<3;i++){
cin>>c[i];
}
}
//输入经度
int leap_year(int year){
if(((year%400==0) || (year%100!=0) && (year%4==0))) return 1;
else return 0;
}
//判断是否为闰年:若为闰年,返回1；若非闰年,返回0
int days(int year, int month, int date){
int i,a=0;
for(i=2000;i<year;i++){
if(leap_year(i)) a=a+366;
else a=a+365;
}
if(leap_year(year)){
for(i=0;i<month-1;i++){
a=a+days_of_month_2[i];
}
}
else {
for(i=0;i<month-1;i++){
a=a+days_of_month_1[i];
}
}
a=a+date;
return a;
}
//求从格林威治时间公元2000年1月1日到计算日天数days
long double t_century(int days, long double UTo){
return ((long double)days+UTo/360)/36525;
}
//求格林威治时间公元2000年1月1日到计算日的世纪数t
long double L_sun(long double t_century){
return (280.460+36000.770*t_century);
}
//求太阳的平黄径
long double G_sun(long double t_century){
return (357.528+35999.050*t_century);
}
//求太阳的平近点角
long double ecliptic_longitude(long double L_sun,long double G_sun){
return (L_sun+1.915*sin(G_sun*PI/180)+0.02*sin(2*G_sun*PI/180));
}
//求黄道经度
long double earth_tilt(long double t_century){
return (23.4393-0.0130*t_century);
}
//求地球倾角
long double sun_deviation(long double earth_tilt, long double ecliptic_longitude){
return (180/PI*asin(sin(PI/180*earth_tilt)*sin(PI/180*ecliptic_longitude)));
}
//求太阳偏差
long double GHA(long double UTo, long double G_sun, long double ecliptic_longitude){
return (UTo-180-1.915*sin(G_sun*PI/180)-0.02*sin(2*G_sun*PI/180)+2.466*sin(2*ecliptic_longitude*PI/180)-0.053*sin(4*ecliptic_longitude*PI/180));
}
//求格林威治时间的太阳时间角GHA
long double e(long double h, long double glat, long double sun_deviation){
return 180/PI*acos((sin(h*PI/180)-sin(glat*PI/180)*sin(sun_deviation*PI/180))/(cos(glat*PI/180)*cos(sun_deviation*PI/180)));
}
//求修正值e
long double UT_rise(long double UTo, long double GHA, long double glong, long double e){
return (UTo-(GHA+glong+e));
}
//求日出时间
long double UT_set(long double UTo, long double GHA, long double glong, long double e){
return (UTo-(GHA+glong-e));
}
//求日落时间
long double result_rise(long double UT, long double UTo, long double glong, long double glat, int year, int month, int date){
long double d;
if(UT>=UTo) d=UT-UTo;
else d=UTo-UT;
if(d>=0.1) {
UTo=UT;
UT=UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo))))));
result_rise(UT,UTo,glong,glat,year,month,date);
}
return UT;
}
//判断并返回结果（日出）
long double result_set(long double UT, long double UTo, long double glong, long double glat, int year, int month, int date){
long double d;
if(UT>=UTo) d=UT-UTo;
else d=UTo-UT;
if(d>=0.1){
UTo=UT;
UT=UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo))))));
result_set(UT,UTo,glong,glat,year,month,date);
}
return UT;
}
//判断并返回结果（日落）
int Zone(long double glong){
if(glong>=0) return (int)((int)(glong/15.0)+1);
else return (int)((int)(glong/15.0)-1);
}
//求时区
void output(long double rise, long double set, long double glong){
if((int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<10)
cout<<"The time at which the sun rises is "<<(int)(rise/15+Zone(glong))<<":0"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<" .\n";
else cout<<"The time at which the sun rises is "<<(int)(rise/15+Zone(glong))<<":"<<(int)(60*(rise/15+Zone(glong)-(int)(rise/15+Zone(glong))))<<" .\n";
if((int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<10)
cout<<"The time at which the sun sets is "<<(int)(set/15+Zone(glong))<<": "<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<" .\n";
else cout<<"The time at which the sun sets is "<<(int)(set/15+Zone(glong))<<":"<<(int)(60*(set/15+Zone(glong)-(int)(set/15+Zone(glong))))<<" .\n";
}
//打印结果
int main(){
long double UTo=180.0;
int year,month,date;
long double glat,glong;
int c[3];
input_date(c);
year=c[0];
month=c[1];
date=c[2];
input_glat(c);
glat=c[0]+c[1]/60+c[2]/3600;
input_glong(c);
glong=c[0]+c[1]/60+c[2]/3600;
long double rise,set;
rise=result_rise(UT_rise(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date);
set=result_set(UT_set(UTo,GHA(UTo,G_sun(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))),glong,e(h,glat,sun_deviation(earth_tilt(t_century(days(year,month,date),UTo)),ecliptic_longitude(L_sun(t_century(days(year,month,date),UTo)),G_sun(t_century(days(year,month,date),UTo)))))),UTo,glong,glat,year,month,date);
output(rise,set,glong);
system("pause");
return 0;
}\x09