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如图,已知AB∥CD,∠1等于∠2.说明BE∥CF

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如图,已知AB∥CD,∠1等于∠2.说明BE∥CF
∵AB∥CD已知
                                                                                  ∴∠ABC=∠DCB两直线.内错  .
                                                                        ∵∠1=∠2已知
                                                                                     ∴∠ABC-∠1=∠DCB-∠2(                              )
                                                                              即            ∠EBC=∠FCB           
                                                         ∴BE∥CF内错.两直线          
                                                  只写括号里的,是不是等式性质1啊?      
                                                       
如图,已知AB∥CD,∠1等于∠2.说明BE∥CF
对,等式性质.等式两边同加或减一个等量,等式值不变
再问: 性质1吗
再答: 等式性质好像只有一个....反正我只学了一个