提问GRE数学题1.If M is the least common multiple of 90,196,and 30

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提问GRE数学题
1.If M is the least common multiple of 90,
196,and 300,which of the following is not a factor of (A)600 (B)700 (C)900
(D)2100 (E)4900
我能算出M=2^2x3^2x5^2x7^2,但不知如何算出factor of M；另外,为何每个质数取较大指数相乘得最小公倍数?既然是最小公倍数为何不是取最小指数的相乘?
2.If n is a positive integer greater than
400,the remainder is 1 when n is divided by 5,6 or 7,what is the value of
我知道有个公式是y=kx+b,表示y除以x,商是k,余数是b.按照此思路如何解这道题?
3.If 10^50-74 is written as an integer in
base decimal notation,what is the sum of the digits in that integer?
4.v^*=v-v/3,if (v^*)^*=8,then v=?

1.factor意思是M的因子.题目中的意思也就是说,下面那个数不能被M整除.你算一下,A不能.相除得73.5,选A
2.这道题,确定是一道填空题吗?还是选择题.
3.这道题的意思应该是说,将这个科学计数法表示的数写成一个普通的十进制表示的数字后,求这个数字各位数字（digit）的和是多少.你要能区分Number和digit的区别.number是一个数字,比如23就是一个number,而对于这个number来说,它的digits有2个,分别是（tens digit）十位数2和(units digit)个位数3.那下面你会算了吧.直接用那个50个0的数去见那个74呗,从最高位借1,然后结果里出现了48个9,一个2,一个6.所以sum=9*48+2+6=440
4.V=18 .V^*=（2/3）v,所以,再将此数带入进行计算,就是：(2/3)v-[(2/3)v-(2/3)v/(1/3)]=8,解出来,得V=18

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