X+(3X-16)÷25%=10(x+1)
X+(3X-16)÷25%=10(x+1)
x*x+2x+x*x+10x+x*x+25+2x+x*x+1+1+16+x*x+4x*x+9-12x+16x*x+4-1
x+(3x-16)÷25%=10﹙x+1﹚x=? (请写出过程)
解方程:x+(3x-16)÷25%=10(x+1)
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
2x平方+3x=3 (用配方) x(2x-5)=4x-10 x平方+5x+7=3x+11 1-8x+16x平方=2-8x
1x()+2x()+3x()+4x()+5x()+6x()+7x()+8x()加9x()+10x()=1980
1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少
C语言中编写s=1-x+(x*x)/2!-(x*x*x)/3!+(x*x*x*x)/4!知道最后一项的绝对值小于10的-