以2为底的1 log3的对数,
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方程两边同取以3为底的对数:(以下用log代替log3)logxlog2=log(1/3)=-1所以logx=-1/log2x=3^(-1/log2)
A=2根号3/3A属于(2/3,1)B=log(3)*(log(3)*4)/log(4)*(log(3)*4)=2.8864663987286C=log2(sin72°)因为sin72°小于1所以lo
有这个公式呀logB(A)=lgA/lgB
(log以3为底2的对数)的平方
a=lg2/lg9=lg2/2lg3所以lg2/lg3=2ab=lg5/lg(1/3)=(1-lg2)/(-lg3)=lg2/lg3-1/lg3=2a-1/lg3所以1/lg3=2a-b原式=lg12
log3为底数8对数-2log3为底数6对数=3log3为底数2的对数-2(log3为底数2的对数+1)=3a-2(a+1)=a-2;B正确
5的2倍log以5为底3的对数这个是5的2倍log以5为底3的对数的次方吗?如果是的话,原式=4log3²(2)-[log3(32/9)-log3(8)]-5^log5(3²)=(
log(3)2=log(2)3^xln2/ln3=xln3/ln2(ln2)^2=x(ln3)^2x=(log(3)2)^2
log3(x²-10)=1+log3(x)log3(x²-10)=log3(3)+log3(x)log3(x²-10)=log3(3x)x²-10=3xx1=-
a=log89=lg9/lg8=2lg3/3lg2b=log320=lg20/lg3=(1+lg2)/lg3ab=2(1+lg2)/3lg2=(2/3lg2)+1/3ab-1/3=2/3lg2lg2=
LOg1/3(10)=lg10/lg1/3=1/(-lg3)=-1/lg30故有log3(4)>log1/3(10)
log2(3)-log3(4)=log2(3)-2log3(2)=log2(3)-2/log2(3)=[(log2(3))^2-2]/log2(3)=[(log2(3))^2-2log2(2)]/lo
如果你的问题是:log3(x^2+2)=(log3x)+1则是下面答案:先建立方程:x^2+2=3x(X>0)解答上面方程x^2-3x+2=0得到结果:x=1或x=2
log(2)3xlog(3)2=1值互为倒数,不对称公式log(a)bxlog(b)a=1
1/4=2^(-2)所以log3(x)=-2所以x=3^(-2)=1/9
原式=1/2+1+9/2-0=6再问:可以说一下过程么再答:把所有几次方全挪到log前面去,而0.25=1/4所以第二项为1,第三项中根号5=5^1/2,所以第三项为9倍的1/2,而loga1=0,综
p-2=(log316)-(log39)=log316/9
3^m=2,则log3(2)=m,log3(8)—2*log3(6)=3log3(2)-2*(log3(3)+log3(2))=3log3(2)-2*(1+log3(2))=log3(2)-2=m-2
-5log9(4)+log3(32/9)-5^[log5(3)]-(1/64)^(-2/3)=-5[log3(4)]/log3(9)]+log3(32)-log3(9)-3-64^(2/3)=-5lo