分式-2x²分之x-1,3x分之4,4x3

X²-3X分之5X-7=X-1分之2+X-2分之3X²-3X分之5X-7=(X-1)(X-2)分之[2(X-2)+3(X-1)]X²-3X分之5X-7=(X²-

（1）x平方-1分之x平方+x-2=(x+2)(x-1)/(x+1)(x-1)=(x+2)/(x+1)（2）3x平方-9x-12分之x平方+2x+1=(x+1)^2/[3(x-4)(x+1)]=(x+

x-1分之3-x(x-1)分之x+2=03x-(x+2)=02x=2x=1检验：x=1是增根∴方程无解

(x+2)/(x+1)=(x+1+1)/(x+1)=1+1/(x+1)其他一样所以原式=1/(x+1)-1/(x+2)-1/(x-5)+1/(x-4)=(x+2-x-1)/(x+1)(x+2)+(x-

3/(x²+2x)-1/(x²-2x)=03/[x(x+2)]-1/[x(x-2)]=0两边都乘以x(x+2)(x-2)得到3(x-2)-(x+2)=0即2x-8=0所以x=4把x

2/(3x)+3/(2x)+1/x=14/(6x)+9/(6x)+6/(6x)=119/（6x)=1.6x=19x=19÷6x≈3.16666666666

原式=[x²/(x-1)]-x-1=[x²/(x-1)]-[(x+1)(x-1)]/(x-1)=[x²/(x-1)]-(x²-1)/(x-1)=[x²

3/2(x-2)-x/(x-2)=1/23-2x=x-2-3x=-5x=5/3检验：x=5/3是方程的解∴方程的解是x=5/3再问：你那个是2分之3(x-2)-x分之x-2吗？再答：不是的是2(x-2

令a=x²+x则3a=2/a+13a²-a-2=0(3a+1)(a-1)=0a=-1/3,a=1x²+x=-1/33x²+3x+1=0无解x²+x=1

1;=3(x+y)/(x-y)2:x平方/(2x-1-x+1)=x3:=-(2x平方-2x-1)/(3x+1)

（x-1)(x+1)/(x-1)(x^2+x+1)=x^2+x+1分之(x+1)

原分式方程可变形为；5x+2/x(x+1)=3/x+1分式两边同乘公分母得：5x+2=3x解得：x=1检验：当x=1时,公分母x(x+1)不等于0所以x=1是原分式方程的解(/表示除号）再问：你算错啦

(x-1)(x-3)≠0x≠1,x≠3时有意义

原式=(3X-7)/(x^2-3x+2)+(2x-1)/(x^2-x-2)-5x/(x^2-1)=(3x-7)/[(x-2)(x-1)]+(2x-1)/[(x-2)(x+1)]-5x/[(x-1)(X

“数理答疑团”为您解答,希望对你有所帮助.x²+x-2=0x=-2和x=1是分式方程x的平方+x-2分之3=x-1分之x-x+2分之x的增根手机提问的朋友在客户端右上角评价点【满意】即可.

[(x+2)-1]/(x+2)+1-1/(x+9)=1-1/(x+3)+1-1/(x+8)后面的三个仿第一个化简-1/(x+2)-1/(x+9)=1-1/(x+3)-1/(x+8)两边同时减去21/(

x=-3或x=1时无意义因为分式的分母是要求不能为0的,如果为0则没有意义.

1.(x+1)/(x-1)-4/(x²-1)=1都乘以(x+1)(x-1)得到(x+1)²-4=x²-1x=1代人检验是增跟,原方程无解.2.(3x+4)/(3x-5)+

X=4原式=(X-1)/(X-2)-(X-2)/(X-3)=(X-4)/(X-5)-(X-5)/(X-6)左边通分=[X^2-4X+3-X^2+4X-4]/[(X-2)(X-3)]=-1/[(X-2)

3x/(3x-1)+x/(x-1)=2都乘以(x-1)(3x-1)得：3x(x-1)+x(3x-1)=2(x-1)(3x-1)3x²-3x+3x²-x=6x²-8x+2解