分式x²y-y xy² y²约分后的结果为-搜答案-搜狗做题网

(x²+xy)/(x+y)²分子提取公因式x=x(x+y)/(x+y)²分子分母同时除以（x+y）=x/(x+y)x²-y²/（x²-y&s

2x^2y(x-y)/{12xy^2(y-x)}=-2x^2y(y-x)/{12xy^2(y-x)}=-x/6y

约分(x²+xy)/(x+y)²=x(x+y)/(x+y)²=x/(x+y）x²-y²/（x²-y²）=1通分2xy/(x+y)&

原式=（x+y)(x-y)/(x-y)^2=(x+y)/(x-y)

y=3x/5原式=x/(x+3x/5)+(3x/5)/[x-3x/5]-(9x^3/25)/(x^3-9x^3/25)=8/3-3/2-9/16=29/48

(（x-y）(x-y))/((x-y)(x+y))=(x-y)/(x+y).

这已经是最简了,没办法约分了,结果是（x+y)2分之（x+2y)(x-2y)

|3-y|+|x+y|=0，且|3-y|≥0，|x+y|≥0，所以3-y=0，x+y=0，所以y=3，x=-3．所以x+yxy=-3+3-3×3=0-9=0．答：x+yxy的值为0．

分式2x+3yxy中，x、y的值都扩大到原来的2倍，则分式的值缩小为原来的12，故选：B．

约分x²-(y-z)²除以(x+y)²-z²这是个分式![x²-(y-z)²]/[(x+y)²-z²]=(x+y-z)(

最简公分母：（y-1）（y+1）1/y-1=（y+1）/（y-1）（y+1）1/y+1=（y-1）/（y-1）（y+1）原式=-2（x-y）³/x-y=-2（x-y）²

x四次方-y四次方/x平方-2xy+y平方=(x²+y²)(x+y)(x-y)/(x-y)²=(x²+y²)(x+y)/(x-y)

原式=2x²y(x-y)÷[-12xy²(x-y)]把2xy(x-y)约分=-x/(6y)所以商是-x/(6y)

(x-y)/(y-x)³=-1/(x-y)²(x²-9)/(6-2x)=(x+3)(x-3)/[-2(x-3)]=-(x+3)/2(x²-1)/(x-x

x³y-xy³/(x³-2x²y+y²x)=xy(x²-y²)/[x(x²-2xy+y²)]=xy(x+y)(

(4x^2-y^2)/(-2x-y)=(2x+y)(2x-y)/-(2x+y)=-(2x-y)=y-2x

2x（x-y）分之（y-x）²=（x-y）/2x;手机提问的朋友在客户端右上角评价点【满意】即可.再问：那-6ab^6分之15a³b^4呢抱歉这个问题锁了我只能这么问了QAQ

(y+z-x)/{x^2-(y+z)^2}=(y+z-x)/[(x-y-z)(x+y+z)]=-(x-y-z)/[(x-y-z)(x+y+z)]=-1/(x+y+z)

=3x-4y/2x(4y-3x)提取公因式=-[3x-4y/2x(4y-3x)变好,使分子分母可约分=-2x/1