化简(x-3分之1-x^2-1分之x 1)×(x-30-搜答案-搜狗做题网

解答如下图所示：

原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]*x/(x-1)(x-4)*(x-2)²=(x²-4-x²+x)/x(x-2)²*x/(x

原式得：1/(x-3)=2-x/(x-3)两边同时乘以x-3得：2x-6-x=1x-6=1x=7

x^2-x-6分解因式得(x+2)(x-3)x^2-4分解因式得(x-2)(x+2)故(x^2-x-6分之x^2-4+x-3分之x+2)=(x-2)/(x-3)+(x+2)/(x-3)=2x/(x-3

原式=2(x+3)(x-2)/(x-2)²x(x+3)-1/(x-2)=2/x(x-2)-1/(x-2)=(2-x)/x(x-2)=-x

原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x+3)(x+5)]\(x^2+7x+13)=[(1分之x+2)-(1分之x+3)+(1分之x+

x^2-1分之x^2-3x+2除以（x+1分之2x-1-x+1)=(x+1)(x-1)分之(x-1)(x-2)除以【x+1分之2x-1-（x+1）分之x²-1】=(x+1)分之(x-2)÷【

(x+3)/(x²-1)÷[(x+3)(x-1)/(﹣x²+2x-1)]=(x+3)/(x²-1)÷[-(x+3)(x-1)/(x²-2x+1)]=(x+3)/

x平方-6x+8=x²-2×3x+9-9+8=（x-3）²-1=（x-3-1）（x-3+1）=（x-4）（x-2）x平方+x-6=（x-2）（x+3）12+x-x平方=（4-x）（

原式=1/x(x+1)+1/(x+1)(x+2)+...+1/(x+2010)(x+2011)=(1/x-1/(x+1))+(1/(x+1)-1/(x+2))+...+(1/(x+2010)-1/(x

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)=(x²-x-6+x-3)/x(x-3)=

1、x-x-1分之1=1X(X-1)=X-1(X-1)^2=0X=1,经检验X=1是增根,原方程无解.2、1-x分之1-2=1-x²分之3x-x²(1+X)-2(1-X^2)=3X

您好：[(X^2-2X)分之(X+2)-(X^2-4X+4)分之(X-1)]除以x-4/x^3-2x^2=[(x+2)/x(x-2)-(x-1)/(x-2)²]*x²(x-2)/(

1/x(x+1)=1/x-1/(x+1)1/(x+1)(x+2)=1/(x+1)-1/(x+2)后面以此类推原式=1/x-1/(x+1)+1/(x+1)-1/(x+2)+……+1/(x+1998)-1

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6分之x-2=x分之x+3-1

再问：再答：

原式=x(x+2)/(x-1)(x+2)-3/(x-1)(x+2)-(x-1)(x+2)/(x-1)(x+2)=(x²+2x-3-x²-x+2)/(x-1)(x+2)=(x-1)/

(x+1)/(x+2)-1/(x+7)=（x+2)/（x+3)-1/(X+6）(X+2-1)/(X+2)-1/(X+7)=(X+3-1)/(X+3)-1/(X+6)1-1/(X+2)-1/(X+7)=

本人一次只回答一个算了吧或者你分开提问x/(x+2)=x/(x-1)两边乘(x+2)(x-1)x²-x=x²+2x3x=0x=0经检验,x=0是方程的解