30个200-300的随机整数存放在数组a中,找出其中的偶数放在数组b中

Private Sub Command1_Click()Text1.Text = ""Dim A(1 To 1

PrivateSubCommand1_Click()Dima(50),i,nRandomizeFori=1To50a(i)=Int(Rnd*191)+10Printa(i);IfiMod10=0The

PrivateSubCommand1_Click()Dima%(1To20),max%,min%max=50min=100RandomizeClsFori=1To20a(i)=Int(Rnd*51+5

#include#includevoidswap(int&a,int&b){intt;t=a;a=b;b=t;}voidheapadjust(int*a,intn,inti){intt,c;for(t

Dima(9)AsIntegerRandomizea(0)=Int(Rnd()*21+10)Doa(1)=Int(Rnd()*21+10)LoopWhilea(1)=a(0)Doa(2)=Int(Rn

Dima(10)Fori=0To9a(i)=Int(100+100*Rnd)NextiFori=0To8Forj=iTo9Ifa(i)t=a(i)a(i)=a(j)a(j)=tEndIfNextjNe

我已经上机验证过了,正确.思路：产生80个随机数,把这80个随机数由小到大排序,然后从第1个到第80个的顺序挑选偶数,赋值给字符串s1,够10个换行.再从第80个到第1个的顺序挑选奇数,赋值给字符串s

=INT(RAND()*20-10)

Java源程序：importjava.util.Random;publicclassTest21{\x05publicstaticvoidmain(String[]args){\x05\x05int[

Dimy%,x%Fori=1To10x=Int(Rnd*100)'[0,99]Printx;Ifi=1Theny=xElseIfy>xTheny=xEndIfNextiPrint"最小值";x如果是N

OptionExplicitPrivateSubForm_Click()'定义i循环变量,imax存放最大数,imin存放最小数,数组ishuz下标为1-10DimiAsLong,imaxAsLong

PrivateSubForm_Load()RandomizeDimintRndAsIntegerDimstrRndAsStringDimstrOushuAsStringDimiAsIntegerFor

functionsj(i%,a%,b%)aslongDimx%x=Int(Rnd*(b-a+1))+asj=xEndfunctionPrivateSubCommand1_Click()Dimn%,a%

dima(30)fori=1to30a(i)=int(rnd(97+3))ifisprime(a(i))=truethenprinta(i);nextifunctionisprime(xasinteg

其实在楼上各位的基础上做多一点点就可以实现1.生成1-68个数2.另外一列生成随机数3.做排序,按随机数做首要条件再问：还是不懂，能详细地说明一下吗？再答：哪里不懂？再问：就是应该怎么操作的，不好意思

PrivateSubCommand1_Click()DimArr(9)AsLong'用于存放产生的10随机数DimiAsLongDimnMaxAsLong'用于存放最大的偶数DimnMinAsLong

题目的含义混淆啊保证相同整数的个数为偶数,这就不叫随机了而且随机生成正数,是不会出现整数的,在这种情况下相同整数的个数总为0,满不满足条件?

PrivateSubCommand1_Click()DimZs(1To35)AsIntegerFori=1To35RandomizeZs(i)=Int(61*Rnd)+20PrintZs(i);Nex

PrivateSubCommand1_Click()DimiAsInteger,xAsInteger,sAsLongRandomizeFori=1To30x=Int(Rnd*100)+1Printx,

输出结果哪里不对可以说下不?再问：有发代码的图片，有看见么？如果看不见的话，请看私信……拜托了~再答：#include"stdio.h"#include"time.h"#include"stdlib.