搜狗做题网4xy²-4x²y-y³
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 09:59:04
因为x-y=4xy所以x-2xy-y=2xy2x+3xy-2y=11xyx-2xy-y分之2x+3xy-2y=5.5
(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^
4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2=(4xy-x²-2xy-y²)/[xy(x+y)(x-y)]÷[(x-y)(x+2y
xy-[x+2y+(0.5x-2)×(y-2)]=24xy-[x+2y+0.5xy-x-2y+4]=24xy-x-2y-0.5xy+x+2y-4=24xy-0.5xy=24+40.5xy=28xy=5
原式=[4(x+y)-2xy]分之[(x+y)+xy]=[4(3xy)-2xy]分之[(3xy)+xy]=10xy分之2xy=5分之1
x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2=16x^3y^3-49x^3y^3-45^3y^3=-78x^3y^3如果本题有什么不明白可以追问,
(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=1.=3(a-b)/(10ab)*(25a^2b^3)/((a+b)(a-b))=15/2*(ab^2)/(a+
(2x²y-3xy²)-3(x²y-2xy²)+2（x²y-4xy²）=2x²y-3xy²-3x²y+6xy&
原式=-(x+2y)*(x^2-2xy+4y^2)=-(x^3+(2y)^3)=-x^3-8y^3
（4xy+12y)+[7x-(3xy+4y-x)]=4xy+12y+7x-3xy-4y+x=xy+8x+8y=xy+8(x+y)=(-2)+8*3=-2+24=22
即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²
xy+1/xy+y/x+x/y=[(xy)^2+1+x^2+y^2]/(xy)=[(xy)^2-2xy+1+x^2-2xy+y^2+4xy]/(xy)=[(xy-1)^2+(x-y)^2+4xy]/(
∵x-y=4xy，∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112．故答案为：112．
xy+1/xy>=2√（xy*1/xy）=2(当xy=1/xy即xy=1时取等号)x/y+y/x>=2√（x/y*y/x）=2(当x/y=y/x即x=y取等号)当x=y=1时可以同时满足两项的等号要求
x^5+y^5-(x^4y+xy^4)=(x^5－x⁴y)－(xy⁴－y^5)=x⁴(x－y)－y⁴(x－y)=(x⁴－y⁴)(
x^2y+4xy+4y=y(x²+4x+4)=y(x+2)²
题目好像有问题再问：没有问题的
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-
原式=[(x-y)^2/(x-y)+4xy/(x-y)][(x+y)^2/(x+y)-4xy/(x+y)]={[(x-y)^2+4xy]/(x-y)}{[(x+y)^2-4xy]/(x+y)}=[(x
原式={[(x-y)^2+4xy]/(x-y)}{[(x+y)^2-4xy]/x+y}={[x^2-2xy+y^2+4xy]/(x-y)}{[x^2+2xy+y^2-4xy]/x+y}={[x^2+2