5x+2y=25.2,2.5x-y=0.4

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5x+2y=25.2,2.5x-y=0.4
(2x -y)(3x-2y)+(y-x)(2x-5y)

(2x-y)(3x-2y)+(y-x)(2x-5y)=6x²-4xy-3xy+2y²+2xy-5y²-2x²+5xy=4x²-3y²

[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2x

原式=(x²+4xy+4y²-3x²-2xy+y²-5y²)÷2x=(-2x²+2xy)÷2x=-x+y再问:x=-2y=二分之一再答:=5

[(x+2y)的平方-(x+y)(x-y)-5y的平方]除以(2x)

x^2=x的平方‘/’为除以[(x+2y)^2-(x+y)(x-y)-5y^2]/(2x)=[(x^2+4xy+4y^2)-(x^2-y^2)-5y^2]/(2x)=[4xy]/(2x)=2y[(3x

(X+2Y)(5X-2Y)

5x平方+8xy-4y平方

(x-y)的2次方-2(x-y)+(x-y)-5(x-y)

(x-y)的2次方-2(x-y)+(x-y)-5(x-y)=(x-y)²-2(x-y)+(x-y)-5(x-y)=(x-y)²-(x-y)-5(x-y)=(x-y)²-6

已知x,y为实数,且2(x+2y)=x²+y²+5求代数式3x-4y分之x²+y²

2(x+2y)=x²+y²+5整理得(x-1)^2+(y-2)^2=0x=1,y=2(x²+y²)/(3x-4y)=-1

2(2x+3y)(3x+2y)-(6x-y)(2x-5y)

2(2x+3y)(3x+2y)-(6x-y)(2x-5y)=12x^2+26xy+12y^2-(12x^2-32xy+5y^2)=12x^2+26xy+12y^2-12x^2+32xy-5y^2=58

(x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3)

(x+2)(x+3)=x²+5x+6(x-4)(x+1)=x²-3x-4(y+4)(y-2)=y²+2y-8(y-5)(y-3)=y²-8y+15x²

[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)

[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)=(x²-4y²)-(4x²-4xy+y²)+(6x²-17xy+

1、x(x-y)(x+y)-x(x+y)^2

1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)(2a+b)(2

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

数学(x-y)^5*(y-x)^3*(x-y)^2

(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-(x-y)^(5+3+2)=-(x-y)^10

(2x-y)(3x-2y)+(y-x)(2x+5y)

/>(2x-y)(3x-2y)+(y-x)(2x+5y)=6x²-3xy-4xy+2y²+5y²-2x²+5xy-2xy=6x²-2x²-7

1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y

1)(2x+5y)(2x-5y)(-4x^2-25y^2)=-(4x^2-25y^2)(4x^2+25y^2)=-(16x^4-625y^4)=625y^4-16x^42)[(x+y)(x-y)-(x

|x+y+2|+(2x+3y+5)²=0 求x y的值.

绝对值加平方=0因为两者均大于等于0所以都是0|x+y+2|=0(2x+3y+5)²=0x+y=-22x+3y=-5x=-1y=-1有什么不明白可以继续问,随时在线等.

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

5(x-y)^2-(x-y)-8(x-y)^2-3(x-y)

原式=(5-8)(x-y)^2-(1+3)(x-y)=-3(x-y)^2-4(x-y)

.x-y/2x+y/2x和5/x-5+x/5-x

你的题目不够清楚,分子和分母请用括号括起来再问:请快点回答?[x-y/2x]+[y/2x][5/x-5]+[x/5-x][5x/x²2xy+y²]-[5y/x²2xy+y

化简:[(x+2y)^2-(x+y)(3x-y)-5y^2]/2x

[(x+2y)^2-(x+y)(3x-y)-5y^2]/2x=[x^2+4xy+4y^2-3x^2-2xy+y^2-5y^2]/2x=(-2x^2+2xy)/2x=y-x

(2X-3y)-(5x-y)

(2X-3y)-(5x-y)=2x-3y-5x+y=2x-5x-3y+y=(2x-5x)+(-3y+y)=-3x-2y这样写总是全过程了吧