c语言 写两个函数 分别求
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![c语言 写两个函数 分别求](/uploads/image/f/528257-65-7.jpg?t=c%E8%AF%AD%E8%A8%80+%E5%86%99%E4%B8%A4%E4%B8%AA%E5%87%BD%E6%95%B0+%E5%88%86%E5%88%AB%E6%B1%82)
for(i=(x>0x:0);...;...)再问:x>0?x:0这个怎么解释呢??再答:三目运算符首先判断?前面的表达式,为真取值?号后面:号之前的值,为假取值:号之后的值。
#includeintadd(inta,intb){returna+b;}main(){inta,b;scanf("%d%d",&a,&b);printf("a+b=%s",add(a,b));}
#includeintgcd(intm,intn)//最大公约数{intt;if(m
unsignedintaddr(unsignedintnum1,unsignedintnum2){unsignedintsum=0;unsignedintnum3=0;unsignedintnum4=
#include"stdio.h"#definePi3.1415926doublezhouchang(doubler){ doubles;&n
#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}intgongbe
#include#includefloatfun1(floatdisc){\x05if(disc\x05\x05printf("方程无解!");\x05return0;}floatfun2(float
///////////////////////////数组#includeintmain(){inta[3],b[3],sum=0,n;doubleave;printf("输入学生人数\n");sca
//if语句#inlcude#includedefinea10//a自己取值voidmain(){floatx,y;scanf("%f",&x);if(x>=0.5&&x=1.5&&xy=exp(a*
int function(double **p, int p_r,int p_c, double **q,int q_r
#include#includeintlen1,len2;chars1[905];chars2[905];intre[905];voidsub(){inti=0;intj;while(1){if(s1
matrix_mul(int**A,int**B,int**C,intm,intp,intn){for(inti=0;i{for(intj=0;j{C[i][j]=0;for(intk=0;k{C[i
#includevoidmain(){inta,b;printf("请输入两个数:");scanf("%d%d",&a,&b);intgys(inta,intb);intgbs(inta,intb);
#includevoidmain(){chars1[20],s2[10];inti=0,j=0;gets(s1),gets(s2);while(s1[i]!='\0'){i++;}while(s2[j
我已经按你的意思修改了,也运行出来了,希望对你有帮助,代码附带在下面:#include#includefloatt,x1,x2;voidmain(){voidsitu1(floata,floatb,
include"stdio.h"intgongyue(inta,intb);intgongbei(inta,intb);voidmain(){inta,b,temp,gy,gb;clrscr();pr
#includevoidmain(){floatnumber,sum;printf("pleaseinputanumber:");scanf("%f",&number);if(number100000
#includeintcal(intm,intn){intret=0;ret=m%n;returnret;}intmain(intargc,char**argv){intm,n,max,min
按照你的要求,代码编译调试过了.修改N便可以随意输入多少个同学,默认为4.输入格式为:tom7560352015#include#include#include#defineN4structBoy{c
#include//求a和b最大公约数:intyue(inta,intb){intk=1;intt=a>b?b:a;//a大取b,否则取afor(inti=1;i