C语言 用递归函数Xn,并输出结果

#includeintfun1(intn){intsum=1;for(inti=1;i

【1】fac(i);【2】intf;for(;n

#include#defineCOL5//一行输出5个longfibonacci(intn){//fibonacci函数的递归函数if(0==n||1==n){//fibonacci函数递归的出口re

#includedoubleH(intn,doublex){if(x>1){if(n==0)return1.0;//H0(x)=1;if(n==1)return2.0*x;//H1(x)=2x;//直

#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)

#include#includeintmax(inta,intb){if(a>b)returna;if(a

#include<stdio.h>voidmain(){      intn=0,i,e=0,x=0,d=0,v=0; 

不用那么麻烦inta=1,b=2,i,k,n;floatsum=0.0;scanf("%d",&n);for(i=0;i再问：不是题目要用递归函数

#includemain(){intx,n;longf(intx,intn);scanf("%d%d",&x,&n);printf("%ld",f(x,n));system("PAUSE");}lon

#includeinttest(inttotal,intcount){if(count==6)//如果分五次之后仍满足要求,则该数为所求{return1;}if(total%5!=1)//如果不满足分

voidprt(intn){printf("%d",n%10);if(n>10)prt(n/10);}intmain(void){inta;printf("请输入整数：");scanf("%d"

elsey=3*x+1；后面的封号是汉字的

#include <stdio.h>char* dg(char* instr, char* outstr, char* 

intFibona(intn){intm;if(n==1)return(1);elseif(n==2)return(1);else{m=Fibona(n-1)+Fibona(n-2);return(m

#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\

#include#include#includeintmain(void){srand(time(0));inti=0;//用于下面的循环inta[20]={0};//用于存储产生的20个随机数.do

要写出递推式：f(x,n)=1+x*f(x,n-1)doublef(doublex,intn){if(n==0)return(1.0);elsereturn(1.0+x*f(x,n-1));}

1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n

把你的printf("*/n")改为printf("*\n"),其它的/n也改为\n看看行不行.#include#includeintmain(){doubley;doublex,m,i;for(y=

intN(intx){if(x==0){return1;}else{returnx*N(x-1)}}intiRet=0;for(inti=1;i