C语言编写程序,计算并打印若干个整数的平均值,直到输入9999结束-搜答案-搜狗做题网

//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV

#include"stdio.h"voidmain(){inti,j,k,n,a[25];printf("请输入一个数：\n");scanf("%d",&k);if(k/2==(float)k/2)\

#includemain(){doublex,y;scanf("%lf",&x);if(x

dimiaslongdimsumaslongsum=0fori=1to100step2sum=sum+inextiprintsum

#includemain(){inta,b,c;scanf("%d,%d,%d",&a,&b,&c);printf("%d\n",(a>b?a:b)>c?(a>b?a:b):c);}

TCHARszBuff=newTCHAR[10000];这里把所有的内容放到szBuff里intaverage,iWordNum,iLine;while(*szBuff++!='\0'){if(*sz

#include#include#includeintmain(){inti,a[200]={0};charc;for(i=0;;i++){scanf("%c",&c);if(c=='\n')brea

#include<stdio.h>int main(void){ int n,count = 0;&n

#includevoidmain(){intx,y,z,j=0;printf("一百只驴驮一百旦\n");for(x=0;x再问：有错误 if(z%2==0&&3*x+2*y

#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fact(n-1);}intmain(){printf("5!+10!=%d\n"

我刚刚编的,可以.不知道是不是你所要的.#includevoidmain(){intn;printf("欢迎来到计算整数的三次方的程序!\n");printf("请输入您要计算的数:");scanf(

#include"Stdio.h"intmain(void){inti,j;for(i=5;i>0;i--){for(j=1;j

#include#defineM7voidmain(){\x09inta[M][M],i,j;\x09for(i=0;i

#include <stdio.h>int main(){ float x, tax = 0;

#includeintmain(){inti,j;charstr1[20]="ABCDEFGHIABCDE";for(i=0;i

“i=1”---->"i==1","i=2"------>"i==2"

因为3个加法的运算规律是相同的,使用一个函数来计算循环值#includeintfun(intn)//计算累加结果函数{//这里还可以判断下n是否小于等于0intsum=0;inti;for(i=1;i

main(){inta,b,c;c=a+b;scanf("%d%d",&a,&b);printf("%d",c);}

#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i

m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.