c语言输入10个数,将最大值与最小值交换
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#includevoidfun(doublea[10],intn){inti;doubleave,max,min,sum=0;max=a[0];min=a[0];for(i=0;i
#include#include#include#defineN10voidmain(){inti,j,p[10],temp;for(i=0;i
#include<stdio.h>voidinput(intb[10]){inti;for(i=0;i<10;i++)scanf("%d",&b[i]);
#includevoidmain(void){intA[10],max,min,num=0,all=0;//数组,最大数,最小数,大于平均数的个数,所有数之和doubleave=0.0;//平均数pr
程序你看看吧,有问题再问,/>#include<stdio.h>int main(){ int i,t,t1; int a[10];&nb
#includevoidmain(){inta[10],min,max,i,k;for(i=0;i
供参考……#include"stdio.h"//voidmain(void){intnDec[10]={7,1,9,2,6,0,3,5,4,8},i,max,min;printf("Type10int
main(){intmax,min,i,x;floatave;scanf("%d",&x);max=min=ave=x;for(i=0;imax)max=x;if(x
#includeintmain(){inti,max,min,maxnum,minnum;inta[10]={0};for(i=0;i再问:有些不懂啊?怎么是intmain?inta[10]只定义不赋
#include#include#defineLENGTH20voidmain(){int*pBuff=(int*)malloc(sizeof(int)*LENGTH);inti,max,min;fo
#include"stdio.h"voidmax_min(int*a,intindex,intend);//声明函数voidmain(){inta[10],i;//定义数组a用来存储10个整数for(
#includeintmain(){inti,max,min,n,a[105];scanf("%d",&n);scanf("%d",&a[1]);max=a[1];min=a[1];for(i
#includeintmain(){printf("Pleaseinput10number.\n");inta;scanf("%d",&a);intmax=a,min=a;for(inti=0;i
#include <stdio.h>#include <stdlib.h>int main(){ int i,&n
#include <stdio.h>int main(){ int n=10;  
#include<stdio.h>#include<string.h>void Input(int *num){ &nbs
voidmain(){inta[100],i,j;intmax,min,aver;\x05charc;\x05i=0;\x05aver=0;\x05printf("请输入N个数\n");\x05do\
in(){intmax,min,i,x;floatave;scanf("%d",
main(){intnumber[10];aa(number);bb(number);cc(number);}aa(int*array){inti;for(i=0;i
你的有两个明显的错误1scanf("%d",a[i]);输入数据应该取地址&a[i]2for(j=0;ja[j])j=0时a[j-1]的下表就是a[-1]这绝对是个大错.再问:#includeintm