用C语言 求和:S=2 22 222 2222;

#includemain(){inti=1,j=1;intsum=0;for(j;j

//VC6.0编译运行通过//求和s=1!+3!+5!#include//求阶乘函数intf(intn){if(1==n){return1;}returnf(n-1)*n;}//main函数intma

#includeintmain(){intt=1;inti;ints=0;for(i=2;i

#includemain(){\x09intm,sum=0;\x09for(m=1;m

其实这个题目根本不用求出S,也不用担心它会超出int范围.因为是数列,所以就要从数列规律上去找结果.比如a=1,n=5,s=3.列竖式111111111111111------12345后3位是345

#includeintmain(){inti;intn,a,s,temp;scanf("%d%d",&n,&a);s=a;temp=a;for(i=2;i

floatsum=0.0f;floatu,a,b;while(1){scanf("%f%f",&u,&a);b=u+a;sum+=b;printf("这里是每次输入和:%f",b);printf("这

#includeintmain(){intn,i;while(scanf("%d",&n)!=EOF)/使用EOF/{longsum=0;for(i=1;i

#include"stdio.h"/////////不知道是否正确,希望有帮助.doublex;doublejiecheng(doublea){//介乘.doublei=0;doubler=1;for

两个函数求和?是两个数求和的函数吧!intadd(inta,intb){returna+b;}intmain(){intsum;int(*fn)(int,int);fn=add;sum=fn(3,5)

楼主贴代码,我好给你改啊#include<stdio.h>int main (void){    int sum&nb

#include#includeintSum(intn){inti,s=0;for(i=1;i

#include#includeusingnamespacestd;intmain(){\x05\x05inta,b;\x05intnum;\x05intt=10,d=100;\x05srand((u

话说楼上的······#includevoidmain(){\x09intsum=0,n,m=1,i,j;\x09scanf("%d",&n);\x09for(i=1;i再问：是这个了不过为什么内循环

为了方便,用整数相加举例.#includevoidmain(){inta,b,c,sum;printf("请输入3个数用来相加:\n");scanf("%d%d%d",&a,&b,&c);sum=a+

#include <stdio.h>int main(){int a,b;scanf("%d%d",&a,&b);prin

#include<stdio.h>main(){\x09int a,b,c,s=0;\x09for(a=1;a<=10;a++)\x09{\x09  &

循环条件里可以有scanf.这样while(scanf("%d",&n)!=EOF)就可以#includeintmain(){intn,a,i,s;while(scanf("%d",&n)!=EOF)

#includevoidmain(){inti,j;inttemp,res1=0,res2=0;for(i=0;i

#include#includeintmain(void){\x05intm;\x05scanf("%d",&m);\x05while(m--){\x05\x05intn,i;\x05\x05doub