由方程x^3 y^3 xy-1=0,求lim(3y x-3) x^3

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由方程x^3 y^3 xy-1=0,求lim(3y x-3) x^3
设y=y(x) 由方程x^3+y^3=e^xy 确定,求 dy/dx!x=0的值

x^3+y^3=e^xy对x求导3x²+3y²*y'=e^(xy)*(xy)'3x²+3y²*y'=e^(xy)*(y+x*y')3x²+3y&sup

设y=y(x)是由方程xy+e^y=y+1所确定的隐函数,求d^2y/dx^2 x=0

xy+e^y=y+1(1)求d^2y/dx^2在x=0处的值:(1)两边分别对x求导:y+xy'+e^yy'=y'y/y'+x+e^y=1(2)(2)两边对x再求导一次:(y'y'-yy'')/y'^

我还有一题不会,y=y(x)由方程x^3+y^3-3xy=1,求dy/dx

一样的两边对x求导3x^2+3y^2*dy/dx-3(y+x*dy/dx)=0化简dy/dx=(x^2-y)/(x-y^2)这里3xy(x)求导3[x'*y(x)+x*y'(x)]有不明白的追问再问:

求解微积分方程3道!1.(x^2+1)y'=xy求解微积分方程 2.y''+8y'+41y=0求解微积分方程 3.y''

1.(x^2+1)(dy/dx)=xydy/y=xdx/(x^+1)dy/y=d(x^+1)/2(x^+1)两边同时取积分:ln|y|=0.5ln|x^+1|y=正负根号(x^+1)2.求特征方程λ^

求由方程e^xy=2x+3y-2确定的隐函数y=f(x在(0,1))处的切线方程

两边对x求导,(y+xy')e^xy=2+3y'代入(0,1)1=2+3y',y'=-1/3(y-1)=-x/3整理,得x+3y-3=0

设y=y(x)由方程e^y-xy=0所确定,求y'(x)

这是一个复合函数求导,y=y(x)所以求e^y的导数首先对整体求导,再对y求导即为e^y*y'xy的导数为y+x*y'(根据求导规则)所以两边求导可得e^y*y'-y-x*y'=0

函数y=y(x)由方程e^xy+ln y/(x+1)=0确定,求y(0),

直接在等式中零,x=0,y=y(0),可得关于y(0)的方程解出y(0)即可.具体:e^0*y(0)+lny(0)/1=0即-y(0)=lny(0)作图y1=-x,y2=ln(x),两者的交点的横坐标

设z=f(x,y)是由方程e^z-Z+xy^3=0确定的隐函数

e^z-z+xy^3=0偏z/偏x:z'e^z-z'+y^3=0y^3=z'(1-e^z)z'=y^3/(1-e^z)偏z/偏y:z'e^z-z'+3xy^2=0z'=3xy^2/(1-e^z)偏z/

设函数z=z(x,y)由方程x+2y-z=3e^(xy-xz)确定,则dz(0,0)=?

x+2y-z=3e^(xy-xz)两边对x求导,z看成是x的函数求偏导得,y看成常数,得1-əz/əx=3(y-z-xəz/əx)e^(xy-xz)=><

设函数y=y(x)由方程xy+e^y=1所确定,求y"(0)

xy+e^y=1e^y(0)=1y(0)=0xy'+y+e^yy'=00+y(0)+y'(0)=0y'(0)=0xy''+y'+y'+e^yy''+(y')^2e^y=00+2y'(0)+y''(0)

由已知x+y=-2,xy=3那么2(x+xy)-[(xy-3y)-x]-(-xy)等于多少?

2(x+xy)-[(xy-3y)-x]-(-xy)=2x+2xy-xy+3y+x+xy=3x+3y+2xy=3(x+y)+2xy=3*(-2)+2*3=0

设y(x)由方程e^y-e^x=xy 所确定的隐函数 求y' y'(0)

e^y-e^x=xy两边求导,得e^y*y'-e^x=y+xy'(e^y-x)y'=(e^x+y)所以y'=(e^x+y)/(e^y-x)x=0时,e^y-e^0=0,则e^y=1,则y=0所以y'(

由方程e^xy +y^3-cos(x-y)=0所确定的隐函数的导数

对两边取对数:xy+3lny=lncos(x-y)两边同时对x求导:y+xy'+y'*3/y=-tan(x-y)*(1-y')整理得:y'=tan(x-y)+y/tan(x-y)-x-3/y不知道对不

设y=y(x)由方程e^xy+cos(xy)=y确定,求dy(0).

x=0时,代入方程得:1+1=y,得:y=2对x求导:(y+xy')e^xy-sin(xy)*(y+xy')=y'将x=0,y=2代入得:2=y'故dy(0)=2dx

设函数y=y(x)由方程e^y+xy+e^x=0确定,求y''(0)

/>e^y+xy+e^x=0两边同时对x求导得:e^y·y'+y+xy'+e^x=0得y'=-(y+e^x)/(x+e^y)y''=-[(y'+e^x)(x+e^y)-(y+e^x)(1+e^y·y'

解方程x²-xy-3x=0,x²+y+1=0

x²+y+1=0→y=-x²-1①x²-xy-3x=0②①代入②得,x²-x(-x²-1)-3x=0→x³+x²-2x=0→x(x

函数y=y(x)由方程x^3-3xy^2+2y^3-32=0,且f(x)求导,试求f(x)的极值.

两边对x求导:3x^2-3y^2-6xyy'+6y^2y'=0得y'=(y^2-x^2)/[2(y^2-xy)]=(y+x)/(2y)令y'=0,得y+x=0,将y=-x代入原方程:x^3-3x^3-