java输出1到100之内所有不能被3整除的数-搜答案-搜狗做题网

publicclassA3{publicstaticvoidmain(String[]args){for(inti=1;i

#include<stdio.h>intmain(){ printf("%d",count(100)); &nb

publicclassTest{publicvoiddisplay(){intsum=0;for(inti=0;i

publicstaticvoidmain(String[]args)throwsIOException{inti=0;intcount=0;while(i

importjava.math.BigDecimal;publicclassTest{publicstaticvoidmain(String[]args){BigDecimalmul=newBigDe

#includevoidmain(){inti=1,a=0,b=0;for(i;i

publicclassTest{publicstaticvoidmain(String[]args){intsum=0;inti=2;while(i

在100之内,随便取2个数（如：20,1）,然后组成一个数组如下[20,1,8,8,8,8,8,8,8,8],随即就ok了,绝对80%.不过这种题目太无耻了,典型的抽奖作弊.

public class Test {\x09public static void main(String args[])&nbs

首先实现做一个SortedMap,这个Map的Comparator是根据字母顺序排列的一个规则.（参考java编程思想11章9节.1）把这个map实现出来以后就简单了.把整个文章用space做分割,然

#include"math.h"main(){intm,i,k,h=0,leap=1;printf("\n");for(m=101;m

#inlcdue#defineN100intfactor(intp){inti,sum=0;for(i=2;i

publicstaticvoidmain(String[]args){for(inti=0;i

publicstaticvoidmain(String[]args){\x09\x09for(inti=1;i

intsum=0;for(inti=9;i

1vari,c11,c7:integer;beginc11:=0;c7:=0;fori:=1to100doifimod11=0theninc(c11)elseifimod7=0theninc(c7);

import java.util.ArrayList;public class Test {public static void

#includeintmain(){inti;intsum=0;for(i=1;i{if(0!=i%7){sum+=i;}}printf("sum=%d\n",sum);return0;}

给个代码你publicvoidtest(){intnum=0;intsum=0;for(inti=0;i

includemain(){inti,j=0;for(i=1;i