编写程序求出区间[ 100,300]内的所有素数,并按一行7个数的格式显示结果.-搜答案-搜狗做题网

#includevoidmain(){longi;intj;printf("Pleaseinputnumber:");scanf("%ld",&i);for(j=999;j>=100;j--)if(i

include<stdio.h>int main(void){ int i= 0 , sum

#includemain(){inta,b,c,d,max,min;scanf("%d,%d,%d,%d",&a,&b,&c,&d);max=a;min=a;if(b>max)max=b;if(c>m

#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09printf("商为%.2f余数为%d\n",1.0*a/b,a%b);\x09ret

s=0a=1INPUTnDOb=nMODaIFb=0THENs=s+aENDIFa=a+1LOOPUNTILa>nPRINTsEND

fori=100to500ifimod5=4andimod7=2thensum=sum+1nextprintsum再问：这是完整的吗我是新手不好意思麻烦一个完整的要直接刻通过的再答：将它放入按钮事件即

这样才完整：判断不出错.N-1省去了许多判断,提高了效率.PrivateSubCommand1_Click()DimNAsIntegerDimiAsIntegerIfIsNumeric(Text1.T

没必要这么复杂 #!/bin/shfor i in `seq 100 `do read var echo&nb

intsum=0;for(inti=100;i

s=0k=0fori=1to100s=s+iifi%2=0k=k+iendifendfor?"s=1+2+3++100=",s?"1-100的偶数和：",k

#include"stdio.h"#include"math.h"voidmain(){intm,n,a,b,c,d,flag=0;for(n=int(sqrt(1000));n

1.你用自己的方法将这N个数字分别用数组a(1)-a(n)表示2.求最大fori=1ton-1ifa(i)>a(i+1)thenmax=a(i)elsemax=a(i+1)endifnexti3.求最

#includeintmain(){inti,a,b,c;for(i=100;i

#include<math.h>voidmain(){intn1,n2,n3,n;printf("所得的数为：\n");for(n=100;n<1000;n++){n1=n%10;n

for(inti=1;i再问：{cout

cleari=0dowhilei

%主函数functiontest()x=[];fori=1:200flag=isprime(i);ifflagx=[x,i];endenddisp('1-200之间的质数有:');xend%子函数fu

#includeboolprime(intn){inti;if(n==1)return0;for(i=2;i*i

#include#includevoidmain(){inti,j,sum=0,s;for(i=3;i{s=sqrt((double)i);for(j=2;j{if(i%j==0)break;}if(

clearFORI=1TO100IF(i%4=0.or.i%7=0).and.(i%280)ENDIFENDFORreturn