编程:输入一个整数,判断它能否被3.5.7整除
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 07:44:36
#includeusingnamespacestd;classZ_chu{public:voidjudge(intn);};voidZ_chu::judge(intn){if(n%3==0&&n%5=
#includevoidmain(){intN,status=0;printf("输入这个数:");scanf("%d",&N);if(N%3==0)status++;if(N%5==0)status
#includeusingnamespacestd;voidjudge(intx,inty){if(x%y)return0;cout
我把SCANF里的中文去掉就正常了.
main(){intnum;printf("请输入一个整数:\n");scanf("%d",&num);if(num%2){printf("\n这是一个奇数\n");}else{printf("\n这
#includeintmain(){intnum;inta;//百位intb;//十位intc;//个位scanf("%d",&num);a=num/100;//默认强制转为整型b=(int)(num
#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%5==0)c=1;if(a%7==0)d=1;elseif(c==1&&d==1)p
PrivateSubCommandButton1_Click()DimnNumAsLongIfIsNumeric(TextBox1.Text)ThennNum=Val(TextBox1.Text)If
PrivateSubCommand1_Click()Dima,b,cAsIntegerDimmaxRandomizea=Int(900*Rnd+100)b=Int(900*Rnd+100)c=Int(
以下是关键代码intnum;//这个是要你判断的数if(num%3==0&&num%5==0)//判断能否被整除printf("能被3和5整除");
算法没问题,按你的代码,调整了一下PrivateSubCommand1_Click()Dima!,b!,c!a=Val(InputBox("请输入a"))b=Val(InputBox("请输入b"))
#includevoidmain(){\x09longa;\x09printf("inputanumber:\n");\x09scanf("%d",&a);\x09if(a%3==0&&a%5==0&
voidmain(){intn;printf("请输入一个整数:");scanf("%d",&n);if(n%3==0&&n%5==0&&n%7==0)printf("\n此数能被3,5,7整除\n"
各位数相加和能被3整除,那么这个数就能被3整除,如258各位数相加等于15,15能被3整除,那么258也能被3整除.能够被5整除的只要各位数是0或5就行啦.15和10都能被5整除.另外,0除以任何数都
很基础的,楼主要好好学习啊#include#includevoidmain(){inti;scanf("%d",&i);for(intj=1;j
#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin
我觉得这才是楼主的意思吧,首先判断能否同时被5和6整除,如果不能再单独判断是否能被5或者6整除.importjava.util.Scanner;publicclassTest{publicstatic
#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%3==0)b=1;if(a%5==0)c=1;if(a%7==0)d=1;if(b*
#include#includevoidmain(){\x09intn,i;\x09scanf("%d",&n);\x09if(n==1)\x09{\x09\x09printf("1isnothing
intnumber;scanf("%d",&number);if(number%3==0&&number%5==0){printf("YES");}else{printf("NO");}