编程实现求分段函数的值x为输入y为输出-搜答案-搜狗做题网

#include<stdio.h>#include<math.h>void main(){float x,y;scanf("%f",&a

#include <math.h>double y(double x) {if (x <= 0) r

刚才题目看错了已修正#include#includeintmain(){intx;scanf("%d",&x);x=x

#include#include#defineEI2.718281828459intmain(void){doublex,y;printf("x=");scanf("%lf",&x);if(

#includeusingnamespacestd;main(){doublex,y;cout

input"输入X的值"toxdocasecasex=12y=x*x+10endcase

#include"stdio.h"doubleY(doublex){returnx-1?1.0/(1+x):0;}intmain(){\x05doublex;\x05scanf("%lf",&x);p

#includeintsign(doublex){returnx>0?1:0;}intmain(){intx;scanf("%d",&x);printf("%d\n",sign(x));system(

#include#includefloatf(floatx){doubley;if(x

窗体上添加2个text,1个commandPrivateSubCommand1_Click()x=Text1.TextIfx>=0Theny=1+x^2Elsey=1-2*xEndIfText2.Te

帮你改了下代码,VC6测试通过,自己看看吧.#includeintmain(){floatx,y;//根据给定的测试用例,x,y应该为float型scanf("%f",&x);//x为float型,所

基于c#的classProgram{staticvoidMain(string[]args){Console.WriteLine("Pleaseenteranumber");inta=int.Pars

double是双精度的浮点型数据,输出使用　%lf格式声明.另外如果为了减少程序执行多分支流程,建议swichcase进行分支处理,这样可以只走一个分支,而不是你现在的走三个if分支.switch()

#include#include#includevoidmain(){doublex,y,temp;cin>>x;if(x==0){exit(0);cout

定义变量x,y;输入x;if(xy=fabs(2*x+5);}elseif(x=0){y=sqrt(x+1);}else{y=3*x+1;}输出y;return1;大体就是这样,因为我不是学c语言的,

if(x>0)y=-1;elseif(x

#include<iostream.h>intsign(doublex){returnx>01:0;}intmain(){intx;scanf("%d",&x);printf

//if()实现#include<iostream.h>#include<math.h>voidmain(){ doublex,y

#include <stdio.h>void main(){\x05int i, j, array[5][5], sum=0;\

编程喜欢不好.不要省略{}有错误提示吗?再问：上面说intx;floaty;这里错了再答：总有错误代码的吧