matlab 一个三位整数各位数字的立方和等于本身则称该数为水仙花数
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用循环结构实现fora1=1:9fora2=0:9fora3=0:9n=a1*100+a2*10+a3;ifn==(a1^3+a2^3+a3^3)printf('%d\n',n);endendende
#includevoidmain(){inta;printf("输入一个三位数");scanf("%d",&a);printf("百位:%d十位:%d个位:%d\n",a/100,a/10%10,a%
这个数写(9.595),精确到百分位约是(9.60),保留整数是(10)
0,3,12,21,30,102,120,123,132,201,210,213,231,312,321,1023,1032,1230,1320,1203,1302,2013,2031,2103,21
programjiwei(input,output);varn,a,b,c:integer;{不必用长整型}beginread(n);{读n}ifn>=100then{是否3位}beginwritel
#includeintmain(){intnum;inta,b,c;scanf("%d",&num);a=num/100;b=(num%100)/10;c=num%10;printf("a=%d,b=
ifx==fix(x)%x为整数%fix(x)为取整end
#includeintmain(void){intnum,hundred,ten,indiv;printf("请输入一个三位整数:");scanf("%d",&num);hundred=num/100
这个看你具体要做什么,浮点转整常用以下几个命令.round(a):四舍五入,比如:round(pi)=3ceil(a):向上取整,比如:ceil(pi)=4floor(a):向下取整,比如:floor
?"水仙花数:"m=100dowhilem
//求100到999之间的数是否为水仙花数,输出水仙花数中的次大值.#includevoidmain(){\x09inta,i,i1,i2,i3,p,t=0;for(i=100;i
#include<math.h>voidmain(){intn1,n2,n3,n;printf("所得的数为:\n");for(n=100;n<1000;n++){n1=n%10;n
一个三位小数的整数部分是0,这个数最大是0.999,最小是0.001.故答案为:0.999;0.001.
简单,用round(x)函数四舍五入.然后与x比较,相等那么就是整数,不等就不是整数.
#includeintmain(void){\x09intnum,i,j,k,sum;\x09printf("输入一个三位整数!\n");\x09scanf("%d",&num);\x09i=num%
PrivateSubForm_Click()DimxAsStringDima%,b%,c%,y%x=InputBox("请输入三位数","提示框")IfLen(x)=3Thena=Val(Mid(x,
5.01、5.02、5.03、5.04望及时采纳,
999/9=111则较小的三位数最大值为111故满足上述条件的三位数有:1009001019091029181039271049361059451069541079631089721099811109
PrivateSubCommand1_Click()DimaAsInteger,bAsInteger,cAsInteger,dAsIntegera=Val(InputBox("输入三位整数"))b=I
intdata=inputdata;if(data>99&&data