螺旋矩阵pascal

个人程度还不够好啊,写了好长才写出来,.：#include#defineMAX500main(){\x09inti=0,j=0,a[MAX][MAX]={0},n,number=1,mod=1;\x0

问一下：对于数据的顺序有没有什么要求?ForExample：Input：       1234   

#include#defineN6inta[N][N];voidgo(inti,intj,intdir,intstart,intfinal);intmain(void){intn;inti,j;for

#include#includevoidmain(){inti,j,n,number=1,a[30][30];printf("PleaseinputanumberN:");scanf("%d",&n)

#include#includevoidmain(){inti=0,j=0,n=0;printf("请输入n:");scanf("%d",&n);//矩阵阶数int**p=NULL;//二维指针,存放

pascalpascalpascal!

programjuzheng;vara:array[1..6,1..6]ofinteger;x:string;f:text;b,c:integer;beginwriteln('shurudizhi,e

给你写个框架吧,快速幂就是二分递归functionquick(varx:array[1..2,1..2]ofinteger);根据你自己的矩阵大小改变vary:array[1..2,1..2]ofin

#include#include#include#defineN5voidmain(){\x09intarry[N][N]={0};\x09int\x09i,j,a,b;\x09intn=1;\x09

#include <stdio.h>//基本思想是将所有数按照螺旋顺序存入2维数组,再输出int main(){\x09int n,u,d,l,r,i,j,&

programex9;vara:array[1..10,1..10]ofinteger;【矩阵10*10】d【判别符号】,n【矩阵大小】,i【横坐标】,j【纵坐标】,m【次数,赋值大小】,x【不好意思

输出结果是以下的样子吗?12341213145111615610987再问：对。再答：以下代码，把矩阵分为五块区域，分别进行填数#include <stdio.h>#define

vara,b,c,i,j,k:longint;x,y,f:array[0..2000,0..2000]oflongint;beginread(a);read(b);read(c);fori:=1toa

vari,j,u,v:integer;n:integer;a:array[1..101,1..101]ofinteger;beginreadln(n);ifn=1thenbeginwrite('1')

staticvoidMain(string[]args){intn=2;intcount=0;Listsz=newList{1,2,3,4,11,9,10,5,15,12,8,6,16,14,13,7

varn:longint;d:array[1..20,1..20]oflongint;i,j,k,t:longint;beginreadln(n);t:=0;fori:=1tondobeginforj

programjuzhen;vara,b,c:array[1..100,1..100]ofinteger;m,n,h,i,j,s,k:integer;beginwrite('m=');read(m);

vari,j,k,sum,kk,n,y,x:longint;a:array[1..21,1..21]ofinteger;procedurework;begink:=k+1;inc(sum);casek

#include#defineN6intmain(void){inti=0,j=0,m=0,n=0,num=0;inta[N][N];do{for(i=m;im;j--)a[i][j]=++num;j

这是noip2014普及第三题本人只做了一个50分的,varn,i,j,k,d,x,y:longint;beginreadln(n,x,y);d:=1;k:=0;i:=1;j:=0;repeatinc