搜狗做题网计算 2(x²)³·x³-(3x³)³ (5x)²·x的七次方
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 18:36:32
==(x+3)(x-2)(x+1)再问：嗯就是想问下最后结果是……?00再答：(x3-x2-2x+3x2-3x-6=x3+2x2-5x-6(x后的数字表示次数）
2x^2·(-x)^2-x·(-x)^3+(-3x^2)·x^2=2x^4+x^4-3x^4=0
=x²+3x-(x²-3x+2)=x²+3x-x²+3x-2=6x-2
(3x^2-2x+1)·3x=3x^2-5x+1（6a^3b^2-9a^2b+3ab）÷3ab=2a^2b-3a+1(2m+3)^2-3m(m-2)-(m+2)(m-2)=(4m^2+12m+9)-(
原式=[x/x(x-3)](x+3)(x-3)=(x+3)(x-3)/(x-3)=x+3
原式=[3x/(x-2)-x/(x+2)]·（(x-2)(x+2)/x）=3(x+2)-(x-2)=2x+8
3x·(x²+x+2)=3x³+3x²+6x-a²·（a+b）+b·（a²-b²)=-a²(a+b)+b(a+b)(a-b)=(a
(x^2+5x+4)(x^2+5x+6)=(x^2+5x)^2+10(x^2+5x)+24=x^4+10x^3+35x^2+50x+24
=3x^12+x^12-2x^12=(3+1-2)x^12=2x^12
原式=(2x+1)(2x-1)/x(3x-1)*x(3x+1)(3x-1)/x³(2x-1)约分=(2x+1)*(3x+1)/x³=(6x²+5x+1)/x³
(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]=1/(x-3)+2/(x-3)-
（x+1)(x-2)(x-3)(x-6)==（x+1)(x-6)(x-2)(x-3)=(x^2-5x-6)(x^2-5x+6)=(x^2-5x)^2-36=x^4-10x^3+25x^2-36
(x+4)·(-2x)-(x+1)(x-1)+(-3x+2)(x+1)=-2x²-8x-(x²-1)+(-3x²-x+2)=-2x²-8x-x²+1-
(﹣x)^4·x^3-x^7-2x^3·(-x)^4=x^4·x^3-x^7-2x^3·x^4=x^7-x^7-2x^7=-2x^7(2x-1)²-2(x-2)(x+6)=(4x²
原式=[x/(x-3)]-[5x/(x²-x-6)]=[x/(x-3)]-(5x)/[(x-3)(x+2)]=[x(x+2)]/[(x-3)(x+2)]-(5x)/[(x-3)(x+2)]=
x/(x^2-1)+(x^2-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1)-2x^3/(x^4-1)=x/(x^2-1)-2x^3/(x^4-1)+(x^2-x
3x/(x-5)-2x/(5-x)=3x/(x-5)+2x/(x-5)=5x/(x-5)
2x*4x-3x=8x平方-3x
原式=（x+3）（x-2）（x+1）
(X-1)(X-2)(X-3)(X-4)=(X-1)(X-4)(X-2)(X-3)=（x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25