搜狗做题网计算(2x-3y)(4x² 6xy 9y²)
来源：学生作业帮助网 编辑：作业帮 时间：2024/06/25 05:03:15
原式=-2x+x^2-3-x^2+2x-1=-4原式=(y+2)(y-2)/(y-3)(y+2)+(y+2)/(y+1)=(y-2)/(y-3)+(y+2)/(y+1)=(y^2-y-2+y^2-y-
(1)=(x-y)(x+1)(x-1)(2)=x(x^2+x+1/4x)=x(x+1/2)^2(3)=4x^2+4xy+y^2-x^2+4xy-4y^2=3x^2+8xy-3y^2=(3x-y)(x+
3x+2=y和11x=y,得到x=1/4,y=11/4,5X+4=Y和7X+6=Y,得到X=-1,Y=-1代入9X+8=y,不成立,方程组无解..
-x^y^7+y^8)(这里有问题,x的几次方?再问：就是一次方再答：(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-xy^7+y^8)(x^2+xy+y^2)=（x^8-x^7y+x^
1/(6x-4y)+1/(6x+4y)-3x/(4y^2-9x^2)=1/[2*(3x-2y)]+1/[2*(3x+2y)]+3x/(9x^2-4y^2)=1/[2*(3x-2y)]+1/[2*(3x
(x-3y)(y+2x)-(4y-3x)(3x+4y)=2x^2-3y^2-5xy+9x^2-16y^2=11x^2-5xy-19y^2
(x+y)(x+y)^2(-x-y)^3=－(x+y）^6
(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问：能详细一点吗?我,初一的再答：(x-y)^2=(y-x)^2=(x-y)^2*(x
(4x²y--9y)/(2x+3)=y(2x+3)(2x-3)/(2x+3)=y(2x-3)
(-x-2y)*(3x-y)=-3x^2-5xy+2y^2
原式=3x-4y+(2y+x)-(x-3y)-6x=-3x-4y+(2y+x)-(x-3y)=-3x-4y+2y+x-x+3y=-3x+y
16(x+y)^8/9(x-y)^8=16/9*[(x+y)/(x-y)]^8哪个好理解用哪个.再问：有过程没。。。再答：这个过程其实没什么好研究的。。。[3(x-y)^2(x+y)^-2/4(x+y
原式=(2x²+8xy-3xy-12y²)-(3x²-6xy+xy-2y²)=2x²+8xy-3xy-12y²-3x²+6xy-x
解代数式得：-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!
(x+4)·(-2x)-(x+1)(x-1)+(-3x+2)(x+1)=-2x²-8x-(x²-1)+(-3x²-x+2)=-2x²-8x-x²+1-
答：(x+y)^2×(-x-y)^3×[-3/4(x-y)^3]×5/6(y-x)^2=[(x+y)^2]×[-(x+y)^3]×(-3/4)×[(x-y)^3]×(5/6)×(x-y)^2=-1×(
（2/3x√9x6x√y/x)(y√x/y-x²√1/x）=2/3*x*3√x6x*√(xy)/xy*√(xy)/y-x²√x/x=2x√x6√(xy)√(xy)-x√x=x√x7
(x-y)^7÷(y-x)^6+(-x-y)^3÷(x+y)^2=(x-y)^7÷(x-y)^6+[-(x+y)^3]÷(x+y)^2=(x-y)+[-(x+y)]=x-y-x-y=-2y
3x-2y-[-4x+(z+3y)]=3x-2y-(-4x+z+3y)=3x-2y+4x-z-3y=7x-5y-z
=12x^2-3xy+6x+4xy-y^2+2y-8x+2y-4=12x^2-y^2+xy-2x+4y-4