计算多项式7 7^2,n由键盘输入
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![计算多项式7 7^2,n由键盘输入](/uploads/image/f/7218478-46-8.jpg?t=%E8%AE%A1%E7%AE%97%E5%A4%9A%E9%A1%B9%E5%BC%8F7+7%5E2%2Cn%E7%94%B1%E9%94%AE%E7%9B%98%E8%BE%93%E5%85%A5)
publiclongpower(intm,intn){if(nreturnm;elsereturnpower(m,n--)*m;}
importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i
#includeintf(intn){if(n==1)returnn;returnn+f(n-1);}intmain(void){intn;scanf("%d",&n);printf("%d\n",f
只要先选出最大的数,然后其他两个数相加大于这个数就可以构成三角形.然后w=(x+y+z)/2;area=sqrt(w*(w-x)*(w-y)*(w-z));
上面这题是:(x^4-8x²y²+16y^4)÷(2y+x)²÷(x-2y)题中x^4-8x²y²+16y^4=(x²)²-2(x
你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs
#includevoidmain(void){intn=0;inti=0;floats=0;floatfTemp=0.0f;scanf("%d",&n);for(i=1;i
#include"stdio.h"intmain(){inta1=1,a2=2,n=0,i=1,tmp=a2;doublesum=0.0;printf("输入n:");scanf("%d",&n);w
#include"stdio.h"main(){intsum=0,j,i,k,n,p=1;scanf("%d",&n);for(i=1;i
#include#includevoidmain(){printf("\n请分别输入a和n,用逗号隔开:");intn=0;inta=0;scanf("%d,%d",&a,&n);intsum=a;f
#include<stdio.h>intmain(){longN,t=1,sum=0,i;label:printf("pleaseinputN(n>1&&n<1
#includelongcountNum(intn){longnum=1;intm=n;while(m){num*=m--;}returnnum;}longcountSum(intn){longi=0
#include"stdio.h"voidmain(){inti,a,n,sum=0;scanf("%d",&n);for(i=0;i
希望能帮到你.#include"stdio.h"intmain(){inti,j,n,s,temp;printf("请输入n的值:");scanf("%d",&n);for(i=1;i
多项式m+n/2=m+1/2n若是单项式应为(m+n)/2=1/2(m+n)理由:先除后加
#include<stdio.h>int fx(int x,int y){int sum=0,a=x;;for(int i=0;i&l
#include<stdio.h>int main(void){int i,j,a,n,sum,total=0;scanf("%d%d",&am
解题思路:熟练掌握整式的运算是解决问题的关键解题过程:最终答案:略
【n^2+n+1】/【n(n+1)】=【n^2+n】/【n(n+1)】+1/【n(n+1)】=1+【1/n-1/(n+1)】其中:1/【n(n+1)】=【(n+1)-n】/【n(n+1)】=(n+1)
PrivateSubForm_Click()DimsAsLongDimt1AsLongs=0Fori=1Tont1=1Forj=1Toit1=t1*jNexts=s+t1NextPrintsEndSu