n层嵌套平方根的计算 c语言递归

#include"stdio.h"intgys(intm,intn){if(n>1){if(m%n!=0){returngys(n,m%n);}elsereturnn;}}intmain(){intm

#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i

#includefun(intx,intn){if(n==0)return(1);elsereturn(x*fun(x,n-1));}main(){intx,n;scanf("%d,%d",&x,&n

#includeintfun1(intn){intsum=1;for(inti=1;i

#include"stdio.h"doublemysqrt(doublea,doublex0){doublex1;x1=(x0+a/x0)/2.0;if(fabs(x1-x0)>0.000000

#include#includeintmain(){doublex1,x2,a;printf("pleaseinputanumble:");scanf("%lf",&a);if(a=1e-5);pri

递归的时候逻辑有点混乱,你看这样写是不是更好#includeintgcd(intm,intn){intg;g=m%n;if(0==g){returnn;}else{returngcd(n,g);}}i

#include#defineN20main(){intf(intn);inti;for(i=1;i

这个东西关键是递归算法的确定,需要一点数学知识.#include//递归计算函数intcalc(intx){if(xif(x==1){return1;}elseif(x==2){return3;}el

longadd(intn){intt=n-1;if(t>1){longresult=n*t;longsum=result+add(t);returnsum;}else{returnn;}}楼上的方法,

#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)

第一个是正确的我来解释doublefun(intn){intm,k,i;doubles=0.0;for(m=3;m

#include#includeintjiecheng(inte,intn){//intx=e;if(n==1)returne;else{returne*jiecheng(e,--n);}}intma

#includeintmain(void){intn;printf("n=?");scanf("%d",&n);doublesum=0;inti;for(i=2;i

#include#includefloatmyfunction(intn,intx){if(0==n){return1;}elseif(1==n){returnx;}else{return((2*n-

longmi(intx,intn){if(n=1)returnn;elsereturn((long)x*mi(x,n-1);}

if(n==1)\x05\x05return1;你可以改成n==0或者改成returnx取其中一种就可以了

原理是一样的,可以参考下面的稍微改一下,自己动手可以学的更多,#include//实现数据的全排序voidswap(int*a,intx,inty)//数据交换{inttemp=a[x];a[x]=a

#include#includefun(intx);intmain(void){char*pszBuff=NULL;inta;inti=1;intsumResult=0;printf("inputai

intN(intx){if(x==0){return1;}else{returnx*N(x-1)}}intiRet=0;for(inti=1;i