输入X值,按照下列公式计算COSX的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/22 02:15:29
#include#includeusingnamespacestd;intmain(){doublex,y;cin>>x;if(x
#include#includevoidmain(){floatx,y;cin>>x;if(x
#includeintmain(){doublesum=0;inti,n;scanf("%d",&n);for(i=1;i
已写好:#include#includeintmain(){floatx,result;printf("请输入x的值:");scanf("%f",&x);if(x
#include#includevoidmain(){doublex;doubley;coutx;if(-2
在D3输入:=CHOOSE(VLOOKUP(B$1&C$1,{"A甲",1;"A乙",2;"B甲",3;"B乙",4},2,),B3+C3,B3-C3,B3/C3,B3*C3)下拉填充或者=CHOOS
首先C我长时间没碰了,但你的程序的问题还是能看出来的,还是看看书吧.main函数就不对,应是main(){程序主体}.if函数没有返回值,你的程序中没必要用这么多花括号,当if或else后只有一句条件
你没指定什么编程语言,不好做.在Excel中也可以,如下:在A1中输入X的值,B1中输入公式:=if(a1
#include<stdio.h>int main(){\x09int x,y;\x09printf("输入x的值:"); \x09sca
#includeintmain(void){doublex;scanf("%lf",&x);if(x{printf("y=0\n");}elseif(x>=0.0&&x{printf("y=%lf\n
#includeintmain(){inti;doublen,s=1,x=1,y=1;scanf("%lf",&n);for(i=1;;i++){x*=n;y*=i;s+=x/y;if(x/y
#include//希望对您有用#includeintmain(){intx,y;printf("Pleaseenterthenumber:");scanf("%d",&x);if(x
varx,j,f,c,c0:real;i:longint;h:integer;beginreadln(x);c:=1;c0:=0;f:=1;h:=1;i:=0;j:=1;whileabs(c-c0)>
已改,看注释#include#includevoidmain(){doublesum,term=1,x;//float的精度不够,改成double就可以了,31.4打印0.00intk=0,sig
voidmain(){floatx,y;cin>>x;if(x=10)y=3*x-11;elsey=2*x-1;cout
#include#includevoidmain(){intn=2;floatx;doublesum=1.0,term=1.0;printf("inputx:");scanf("%f",&x);do{
一看就是学习不用功的.有1+-1+2=2的式子吗?
首先根据你给出的数据得出x=y^2+1,y=√(x-1)当x=37时,y=6.当x=n+1时,y=√n,n的范围是n>=0.√这个符号是根号希望对你有帮助