VFP从键盘输入十个数并计算最大数与最小数之差

#include <stdio.h>int main(){\x09int n,sum=0;\x09scanf("%d",&n);\

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

#includeintmain(){inti,tmp=0,tot=0;doubleans=0;for(i=0;i{scanf("%d",&tmp);if(tmp>0){ans+=tmp;tot++;}

#include <stdio.h>/*使用宏定义LENGTH长度为10*/#define LENGTH 10main (){  

#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a

#includevoidmain(){inta[10];floataver=0;for(inti=0;i

#include#include#defineN5intmain(){inti,j,a[10],sum=0,temp;floataverage;for(i=0;i

//Note:YourchoiceisC++IDE#includeusingnamespacestd;longintSfun(constintN){longintsum=1;if(N==0||N==1

#includevoidmain(){inta[7][4];intsum=0;inti,j;printf("请输入7*4矩阵：\n");for(i=0;i

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

fpc:varn:string;a,b,i:longint;beginread(n);b:=0;a:=length(n);fori:=1toadob:=ord(n[i])-ord('0')+b;wri

*vfp中计算n（从键盘输入的正整数）个实数（从键盘输入）去掉其中最大数和最小数之后的平均值的程序怎么写CLEARINPUT"输入共N个(正整数)个数字："TOnNDIMENSIONsz(nN)INP

OptionBase1PrivateSubCommand1_Click()n=InputBox("请输入一个正整数")Fori=1ToLen(n)Sum=Sum+Val(Mid(n,i,1))Next

#includeintmain(){inti,a,max,min;couta;max=min=a;for(i=1;i>a;if(maxa)min=a;}cout再问：那这句话为什么要改成for(i=1

inputaifmod(a/2)=0?a/2+3endif

#include<stdio.h>voidmain(){floatnum[10],sum=0,avg;inti;for(i=0;i<10;i++){printf("请输入第

main(){intmax,min,x,i;scanf("%d",&x);max=min=x;for(i=0;imax)max=x;if(x

inta[10];for(inti=0;i>a[i];}intaverage=0;for(i=0;i

#include#includeusingnamespacestd;constintN=1000;intmain(){inta[N],i,sum=0,ave;for(i=1;i>a[i];for(i=

clearinput"请输入一个数："toxa=0b=9x=alltrim(str(x))k=len(x)fori=1tokm=substr(x,i,1)n=int(val(m))ifn>aa=nen