搜狗做题网x^2y (x^3 y^3)极限
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(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.（x+y）^2-（x+y）^3=（x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、（x
极限不存在设y=kx^2代入得到：lim((x^2)y+x^5)/(x^4+x^6+2(x^3)y+y^2))(x,y)->(0,0)=lim(x->0)(kx^4+x^5)/(x^4+x^6+2kx
(x+y)(x+y)^2(-x-y)^3=－(x+y）^6
lim(x^2-5y^2)/(x^2+3y^2)=lim(x^2+3y^2)/(x^2+3y^2)-8y^2/(x^2+3y^2)=1-lim8/[(x/y)^2+3]因为不知道x、y的大小.所以li
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
任取ε>0,取δ=ε/7,当0
因为(x-y)/(x+y)=3,则(x＋y)/(x－y)＝1/3则5(x-y)(x+y)-(x+y)/2(x-y)＝5*3-1/(3*2)=15-1/6=89/6
(-x-2y)*(3x-y)=-3x^2-5xy+2y^2
(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-（x-y）^(5+3+2)=-(x-y)^10
(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方=x²-2xy-3y²-x²+4y²-x²+2xy-y²=(x²-
令y=kx代入即可知,极限与k有关,因此极限不存在
第一题极限是负无穷,分子趋于1-e
=(x-y)[(3x+y)-(2x+3y)]*(x-y)=(x-y)*(x-y)(3x+y-2x-3y)=(x-y)(x-y)(x-2y)到底是化简,还是?=(x*x-2xy+y*y)(x-2y)=x
题目抄的有点问题.按照x^3y^2在分母来计算.分子1-根号(x^2+1)=-x^2/(1+根号(x^2+1))等价于-x^2/2.sin(xy)等价于xy,代入得原极限=lim-x^2*(xy)/(
解题思路：根据题意，由整式的运算的知识整理，分析可以求得解题过程：
解代数式得：-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!
(x+y)^2-3(x+y)=(x+y)(x+y-3)
(2X-3y)-(5x-y)=2x-3y-5x+y=2x-5x-3y+y=(2x-5x)+(-3y+y)=-3x-2y这样写总是全过程了吧
原式等于2x^2-xy+6xy-3y^2-8x+4y=2x^2+5xy-3y^2-8x+4y
(x+y)^2-(x+y)^3=(1-x-y)(x+y)^2(x-y)^2-(x-y)^3==(1-x+y)(x-y)^2