x平方 4y平方 4x-12y 13=0
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原式=(x²+y²+2xy)(x²+y²-2xy)/(x+y)²=(x+y)²(x-y)²/(x+y)²=(x-y)
(3x平方-4y平方)+[-(x平方-2xy-y平方)]-[(3x平方-2xy-y平方)]=3x²-4y²-x²+2xy+y²-3x²+2xy+y
xy(x-y)-x(x-y)平方=(x-y)[xy-x(x-y)]=(x-y)[2xy-x^2]=(x-y)*x(2x-y)-a平方+1.9b平方=(b根号1.9+a)(b根号1.9-a)-12xy+
x平方+y平方+2xy分之x平方-4y平方除以x平方+xy分之2y+x=(x-2y)(x+2y)/(x+y)²·x(x+y)/(x+2y)=x(x-2y)/(x+y)
4x^2-9y^2=(2x+3y)(2x-3y)
(z²-x²-y²)-4x²y²=(z²-x²-y²-2xy)(z²-x²-y²+2xy)
4-12(x-y)+9(x-y)²=[2-3﹙x-y﹚]²=﹙2-3x+3y﹚²再问:那个小的2是怎么弄的再答:二次方,就是平方
这是完全平方原式=[3(x-y)]²+2×[3(x-y)]×2+2²=[3(x-y)+2]²=(3x-3y+2)²
(x^2+y^2)^2-4x^2y^2=[(x^2+y^2)+2xy][(x^2+y^2)-2xy]=(x^2+2xy+y^2)(x^2-2xy+y^2)=(x+y)^2(x-y)^2
2x²+y²=8x²/4+y²/8=0a²=8,b²=4,c²=8-4=4,c=2焦点:(0,-2),(0,2),焦距=2c=43
x^2-4y^2-x+2y=(x+2y)(x-2y)-(x-2y)=(x-2y)(x+2y-1)x^2-2x-b^2-2b=(x+b)(x-b)-2(x+b)=(x+b)(x-b-2)
(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!
x8+256y8-32x4y4(用手机打的不要介意,给个最佳答案吧)
x平方-y平方=4(x+y)(x-y)=4(x+y)平方*(x-y)平方=4*4=16
x²-y²+5x+3y+4=(x²+4x+4)-(y²-4y+4)+x-y+4=(x+2)²-(y-2)²+x-y+4=(x+y)(x-y+
=(x²+y²)²-(2xy)²=(x²+2xy+y²)(x²-2xy+y²)=(x+y)²(x-y)
根据:a²-b²=(a+b)(a-b)(x²+y²)²-(2xy)²假设:(x²+y²)²=a²,(
x的平方-x-4y的平方+2y=(x-2y)(x+2y)-(x-2y)=(x-2y)(x+2y-1)
x平方-4y平方-x-2y=(x+2y)(x-2y)-(x+2y)=(x+2y)(x-2y-1)
4x的平方-12xy+6y的平方=(2x)²-12xy+6y²=(2x-2y)*(2x-3y)=2(x-y)*(2x-3y)