y=2x^2-x^4的极值-搜答案-搜狗做题网

f'x(x,y)=e^x(x+2y+y^2+1)=0f'y(x,y)=2e^x(1+y)=0解得x=0y=-1A=f''xx(x,y)=e^x(x+2y+y^2+2)=1B=f''xy(x,y)=2e

对f求x的偏导有：偏导f/偏导x=3x^2-3,令其等于0,解得x=1或者-1再对y求偏导有：偏导f/偏导y=-2y+2,令其等于0,解得y=1.所以极点有：（1,1）或者（-1,1）函数在此点连续,

无极值f(x,y)=x^2y^2-4x^2y-6xy^2+24xy对x求偏导得y(x-3)(y-4)对y求偏导得x(x-6)(y-2)稳定点为{0,0}{0,4}{3,2}{6,4}{6,0}又f对x

y=2x^3-3x^2显然定义域为R,则有y'=6x^2-6x令y'=0则有6x^2-6x=0,解之,得极值点x1=0,x2=1将极值点分别带入方程,得极值y1=0,y2=-1则y'

y=-X^4+2X^2=-(x^2-1)^2+1当X=1时,有最大值为1

函数的导数为：y'=4x-4x^3令y'=0得x=0,x=1x(-∞,0)0(0,1)1(1,+∞)y'++-yx=0无极值x=1有极大值为y=1所以函数的导数为：y'=4x-4x^3,在x=1有极大

y'=-4x^3+4x当y'=0即-4x^3+4x=0时解得x1=0,x2=-1,x3=1函数的增区间(-∞,-1],[0,1]函数减区间[-1,0],[1,+∞)所以f(-1)极大=1f(0)极小=

1.求导,导数为零的点就是极值点,代入求极值1,求导,找到极值点,根据极值点两侧增减性,判断是极大值,还是极小值.然后与－2与2两点的值比较大小,找出极大与极小值.

求y=x/x^2+3的极值

y=x/(x^2+3)y'=[(x^2+3)-x*2x]/(x^2+3)^2=-(x^2-3)/(x^2+3)^2=-(x+√3)(x-√3)/(x^2+3)^2=0x1=-√3,x2=√31.x1=

求偏导对x求偏导得:4-2x对y求偏导得:-4-2y令上面两式等于零得:x=2y=-2所以极值f(x,y)=f(2,-2)=8

求偏导对x求偏导得:4-2x对y求偏导得:-4-2y令上面两式等于零得:x=2y=-2所以极值f(x,y)=f(2,-2)=8

f(x,y)=4(x-y)-x^2-y^2=-(x^2-4x+4)-(y^2+4y+4)+8=-(x-2)^2-(y+2)^2+8

f(x,y)=4(x-y)-x^2-y^2=-(x-2)²-(y+2)²+8因为(x-2)²≥0,(y-2)²≥0所以f(x,y)=4(x-y)-x^2-y^2

f(x,y)=x^3+y^3-2x^2-2y^2+4x=(x^3-2x^2+4x)+(y^3-2y^2)对x求偏导为3x^2-4x+4对y求偏导为3y^2-4y求极值先求一阶导数为0即3x^2-4x+

clear;syms x y;z=4*(x-y)-x^2-y^2;ezsurf(x,y,z)view(-30,15)[x1,y1]=solve(diff(z,x),diff(z,y

对函数求导f'(x)=x^2-2x-3令导函数f'(x)=0即x^2-2x-3=0解得x1=-1,x2=3把定义域分成三个区间(-∞,-1)、(-1,3)、(3,+∞)列下表判断导数的符号x(-∞,-

有10件产品,其中8件正品,2件次品,甲乙先后各取一件,求甲先抽到正品条件下,已抽到正品的概率?这个有答案吗?