y=[1-x平方]分之[1 x平方]求y的值
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[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]/4y=1(x²+y²-x²+2xy-y²+2xy-2y²)/4y=1(4xy-2y
X^2+Y^2=1表示圆,(Y-2)/(X-1)表示过点(1,2)的直线的斜率所以这道题是求过点(1.2)与圆相切的的直线的斜率.设直线为y-2=k(x-1)y=kx-k+2带入圆,x^2+(kx-k
(x分之x的平方-y的平方)乘以(x的平方-2xy+y的平方分之2x)其中x=2y=1=(x^2-y^2)/x*2x/(x-y)^2=(x+y)(x-y)/x*2x/(x-y)^2=2(x+y)/(x
2x-y+1的绝对值+(3x+2分之3y)平方=0则2x-y+1=03x+3y/2=0,则2x-y=-1①2x+y=0②①+②,得4x=-1,则x=-1/4①-②,得-2y=-1,则y=-1/2x+y
x平方-x+1=x平方-x分之6-x+1=-x分之6x-x分之6-1=0x平方-x-6=0(x-3)(x+2)=0x-3=0,x+2=0所以,x=3.x=-2
原式=(x²+2x+1)+(y²-8y+16)=(x+1)²+(y-4)²=0∴x+1=0,y-4=0∴x=-1,y=4y/x=4/-1=-4
x/y=1/2y=2x(x^2+2xy+y^2)/(x^2-xy+y^2)=(x^2+2x*2x+(2x)^2)/(x^2-x*2x+(2x)^2)=9x^2/3x^2=3
y分之x=2分之1y=2x所以原原式=(x²-2x²-8x²)分之(x²+4x²+4x²)=-9分之9=-1
[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x
x的平方+2xy+y的平方分之x的平方-y的平方=(x+y)(x-y)/(x+y)²=(x-y)/(x+y)∵x+y=2,x-y=1∴原式=1/2
再答:不明白的地方可以追问,望采纳,谢谢
X=-1/2Y=-2/3解=-5/9不知道对不对=.=!
7/x(x+1)-6/(x+1)(x-1)=-1/x(x-1)两边乘以x(x+1)(x-1)得7(x-1)-6x=-(x+1)7x-7-6x=-x-12x=6∴x=3经检验:x=3是方程的解
(Y-X)/4x(y-1)-y(x-1)=4推出Y-X=42分之x的平方加y的平方推出X的平方/4+Y的平方=4
解2xy²-[3xy²-2(x²y-1/2xy²)]-2x²y=2xy²-(3xy²-2x²y+xy²)-2x
(1-y+x分之y)÷y的平方-x的平方分之x=[(y+x-y)/(y+x)]÷x/(y²-x²)=x/(y+x)*[(y+x)(y-x)/x]=y-x
x的平方-64y的平方分之2x-x-8y分之1=[2x-(x+8y)]/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)
y分之x=2分之1y=2x所以原原式=(x²-2x²-8x²)分之(x²+4x²+4x²)=-9分之9=-1
x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²
y’=[sinx/(1-x²)]'=[(sinx)'(1-x²)-sinx(1-x²)']/(1-x²)²=[cosx(1-x²)+2xsi