Z=1-X^2-Y^2 Z=0 求质心

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Z=1-X^2-Y^2 Z=0 求质心
已知x、y、z满足方程组:x+y-z=6;y+z-x=2;z+x-y=0 求x、y、z的值

x+y-z=6y+z-x=2z+x-y=0三式相加得x+y+z=8-得2z=2z=1-得2x=6x=3-得2y=8y=4x=3y=4z=1

设函数z=z(x,y)由方程x^2+y^3-xyz^1=0确定,求z/x,z/y

x²+y³-xyz=0,z=(x²+y³)/(xy)=x/y+y²/x;故z/x=1/y+y²/x²z/y=x/y²+y

设X+Y+Z=0求X^3+X^2Z-XYZ+Y^2Z+Y^3的值

因为:X+Y+Z=0得:Z+Y=-X------(1)X+Y=-Z------------(2)Z+Y=-X------------(3)X^3+X^2Z-XYZ+Y^2Z+Y^3=X^3+XZ(X+

|x+1|+|y-2|+|z+3|=0 求 x y z

解|x+1|≥0|y-2|≥0|z+3|≥0∴x+1=0,y-2=0,z+3=0∴x=-1,y=2,z=-3

已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.

因为x:y:z=3:4:5所以设x=3k,y=4k,z=5k(k≠0)(1)z/(x+y)=5k/(3k+4k)=5k/7k=5/7(2)x+y+z=63k+4k+5k=612k=6k=1/2x=3k

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,

x+y+z-6=02x+3y-z-12=02x-y-z=0组成方程组再解x=2y=3z=1

设函数z=z(x,y)由方程e^(-xy)-2z+e^z=0确定,求z/x,z/y

两端对x求偏导得:-ye^(-xy)-2(z/x)+(z/x)e^z=0,所以,z/x=ye^(-xy)/(e^z-2)两端对y求偏导得:-xe^(-xy)-2(z/y)+(z/y)e^z=0,所以,

|X-3|+| Y-2|+|Z-1|=0,求3x+2y +Z的值

由|X-3|+|Y-2|+|Z-1|=0可知X-3=0,Y-2=0,Z-1=0得X=3,Y=2,Z=1所以3x+2y+Z=3×3+2×2+1=14

已知实数xyz满足|x-2y|+2√(2y+z)+z-2z+1=0,求x+y+z的值

x-2y=02y+z=01-2z=0解出来x=-0.5y=-0.25z=0.5快采纳吧~~~再问:给你点个赞再答:O(∩_∩)O哈哈~

1.已知x,y,z满足2│x-y│+(根号2y-z)+z平方-z+(1/4)=0,求x,y,z值.

1.z²-z+1/4=(z-1/2)².绝对值、根号、平方数都是非负的,而相加为0.所以都为0.即x=y,2y=z,z=1/2.所以x=y=1/4,z=1/2.2.2002x200

X+Y+Z=0,X-Y-Z=0,Y=2,求x和z

0和-2再答:0和-2再问:说清是X等于几和z等干几

如果,根号x-3+| y-2 |+z^2=2z-1 求 (x+z)^y

根号x-3+|y-2|+z^2=2z-1根号x-3+|y-2|+(z^2-2z+1)=0根号x-3+|y-2|+(z-1)^2=0由于数值开根号,绝对值和平方数均为大于等于0的数则上式要成立只有X-3

x^2+y^2+z^2+4x+4y+4z+1=0,求x+y+z

x²+4x+4+y²+4y+4+z²+4z+4=-1+4+4+4(x+2)²+(y+2)²+(z+2)²=11[(2-(-x))²

x^2+y^2+z^2+4x+4y+4z+1=0求x+y+z

稍等.再问:……我一直等着再答:这个题目不太对,应该是求X+Y+Z的最小值吧,再问:你的想法是什么?再答:因为x+y+z的值有无穷个答案。。。再问:你是怎么推算的?再问:我是想问这个再答:这很简单啊,

x^2+y^2+z^2+4x+4y+4z+1=0 求x+y+z

x²+4x+4+y²+4y+4+z²+4z+4=-1+4+4+4(x+2)²+(y+2)²+(z+2)²=11[(2-(-x))²

已知x,y,z满足x+y+2z=1,x²+y²+6z+1.5=0,求x,y,z的值

2z=1-x-yx^2+y^2+3-3x-3y+1.5=0(x-1.5)^2+(y-1.5)^2=0x=y=1.5z=-1

已知 3x-y+2z=0 2x+y-3z=0,求x :y :z.

两式相加,得3x-z=0可得z/x=5将z=5x代入1式13x-y=0得y/x=13所以x:y:z=1:13:5

x*x+y*y+2z*z-2x+4y+4z+7=0,求xyz的值

x*x+y*y+2z*z-2x+4y+4z+7=0(x*x-2x+1)+(y*y+4y+4)+2(z*z+2z+1)=0(x-1)^2+(y+2)^2+2(z+1)^2=0x=1,y=-2,z=-1x

若x/2=y/3=z/4不等于0,求x+y+z/x+y-z的值

令a=x/2=y/3=z/4则x=2a,y=3a,z=4a所以原式=(2a+3a+4a)/(2a+3a-4a)=9a/a=9