∫(0,1)arctanx/(x·根号下(1-x^2)) dx
∫x*arctanx/(根号下(1+x^2))dx怎么求
∫(0 1)x(arctanx)^2dx
∫(根号下arctanx/1+x^2)dx ;∫((arcsinx)^2/根号下1-x^2)dx;∫e^xcos(e^x
∫(arctanx)^2/1+X^2 dx
∫(arctanx)^3/(1+x^2)dx
∫1到0 x^(2)arctanx·dx/(x^(2)+1)
求不定积分∫(arctanx)/(x^2(x^2+1))dx
求积分 ∫(arctanx)/(x^2(x^2+1))dx
积分∫arctanx*x^2/(1+x^2)dx
∫[x+e^(arctanx)/ (1+x^2) ]dx=
求不定积分 ∫ x -arctanx / 1+x^2 dx
求不定积分∫x+arctanx/(1+x^2)dx