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{5x-2>3(x+1),1/2x-2≤7-5/2x; {4(x-3)-5x≤-18,(2x-3)/3-(x+1)/2

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{5x-2>3(x+1),1/2x-2≤7-5/2x; {4(x-3)-5x≤-18,(2x-3)/3-(x+1)/2
{5x-2>3(x+1),1/2x-2≤7-5/2x; {4(x-3)-5x≤-18,(2x-3)/3-(x+1)/2
(1)5x-2>3(x+1)
→ 5x-2>3x+3
→ 2x>5
→ x>5/2
1/2x-2≤7-5/2x
→ 1/2x+5/2x≤9
→ 3x≤9
→ x≤3
所以5/2<x≤3
(2)4(x-3)-5x≤-18
→ 4x-12-5x≤-18
→ -x≤-6
→ x≥6
(2x-3)/3-(x+1)/2