设y=e^(-x)cos(3-x),求dy 详细些

来源：学生作业帮编辑：搜狗做题网作业帮分类：数学作业时间：2024/06/09 17:25:16

∵dy/dx=y'=[e^(-x)]'cos(3-x)+e^(-x)[cos(3-x)]'
=-e^(-x)cos(3-x)+e^(-x)(sin(3-x)
=[-cos(3-x)+(sin(3-x)]e^(-x)
∴dy=e^(-x)[-cos(3-x)+(sin(3-x)]dx

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