方程组x^2+y^2=1 y^2+z^2=5 z^2+x^2=4共有几组解
解方程组2x+y-z=7 x+y+z =1 2x-y-z=5
已知方程组4x-5y+2z=0 x+2y=3z 则x:y:z
解方程组:x+y+z=4,x+y+2z=5,3x+y-z=6
已知x.y.z满足方程组x+2y-4z=0 2x+y-5z=0 求x:y:z的值
已知x、y、z满足方程组:x+y-z=6;y+z-x=2;z+x-y=0 求x、y、z的值
解方程组:x-2y+z=-1,x+y+z=2,x+2y+3z=-1
解方程组{z=x+y 3x-2y-2z=-5 2x+y-z=3
解方程组 z=x+y 2x-3y+2z=5 x+2y-z=3
解方程组x-4y+z=-3,2x+y-z=18,x-y-z=7.
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}
x+y/2=z+x/3+y=z/4,...x+y+z=27.解方程组.
求解三元一次方程组:{x+y/2=y+z/3=z+x/4 x+y+z=27