几道初二的分式方程!(1) x+1/x-2加上x+2/x-1=2(2) x-8/x-7减去x/7-x=8(3)x/2x-

分式方程.x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6) x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程 x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8 （解方程） 解分式方程,7/(x^2+x)+3/(x^2-x)=6/(x^2-1) 解一道初一的分式方程（x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)求x的 x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程 解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3 解分式方程[（x＋2)／(x＋1)]＋[(x＋8)／(x＋7)]=[(x＋6)]／[(x＋3)]＋[(x＋4)}／[(x x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)谁会解这道方程题 x/(x-2)+(x+9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)怎样解这道方程 解方程：x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6) 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值