求解微分方程xy'ln(x)sin(y)+cos(y)(1-x*cos(y))=0
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求解微分方程xy'ln(x)sin(y)+cos(y)(1-x*cos(y))=0
![求解微分方程xy'ln(x)sin(y)+cos(y)(1-x*cos(y))=0](/uploads/image/z/18413342-62-2.jpg?t=%E6%B1%82%E8%A7%A3%E5%BE%AE%E5%88%86%E6%96%B9%E7%A8%8Bxy%27ln%28x%29sin%28y%29%2Bcos%28y%29%281-x%2Acos%28y%29%29%3D0)
∵xy'ln(x)sin(y)+cos(y)(1-x*cos(y))=0
==>xln(x)(cos(y))'=cos(y)(1-x*cos(y))
==>xln(x)t'=t(1-xt) (令t=cos(y))
∴xln(x)z'+z=x (令z=1/t).(1)
∵微分方程(1)是一阶线性方程,用常数变易法可求得它的通解是
z=(x+C)/ln(x) (C是积分常数)
∴cosy=t=1/z=ln(x)/(x+C)
故原微分方程的通解是cosy=t=1/z=ln(x)/(x+C) (C是积分常数).
==>xln(x)(cos(y))'=cos(y)(1-x*cos(y))
==>xln(x)t'=t(1-xt) (令t=cos(y))
∴xln(x)z'+z=x (令z=1/t).(1)
∵微分方程(1)是一阶线性方程,用常数变易法可求得它的通解是
z=(x+C)/ln(x) (C是积分常数)
∴cosy=t=1/z=ln(x)/(x+C)
故原微分方程的通解是cosy=t=1/z=ln(x)/(x+C) (C是积分常数).
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