求最值 y=-2sin(3x+π/4) (0≤x≤π/2)
函数y=3sin(2x+π4
函数y=2sin(3x+π4
证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+
y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
y=sin(-3x) =-sin3x y=cos(3x+π\4) =cos(π/2+3x-π/4) =-sin(3x-π
0≤x≤π/2,求函数y=sin(2x+π/3)的值域
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
已知函数y=2sin(2x-π/4)-2根号2sin^2x
1.y=x*e^(2x) 2.y=(sin(2x))/x 3.y=sin(3x+(π/3))怎么求导数!
求x^2-y^2二重积分,D:0≤x≤π,0≤y≤sin x
y=sin2x y=sin(x+π/3) y=3sin(2x+π/3)
设函数 f(x)=sin(2x+y),(-π