求教一道高数极限问题x趋向于1.lim(x) sin(pai x)/(x-1)=lim pai cos (pai x)=

求极限,lim x趋向于pai/2-0 cosx的pai/2 -x次方 高数求极限 帮下忙1.Lim X趋向0,SIN5X^2/(TAN2x)^22.Lim X趋向PAi SINX/X-PAI 求极限lim[sinx/(x-pai)] x趋于pai f x =sin(pai*x/4-pai/6)-2(cos pai*x/8)^2+1 x趋向0 lim cos(1/x),x趋向pai/2 tanx 化简!f(x)=sin(pai-x)cos(3/2pai+x)+sin(pai+x)sin(3/2pai-x) lim(sinx)^tanx (x趋向于pai/2) 求极限:lim(sinx)^tanx (x趋近于pai/2) f(x)=(1+cos2x)/[4sin(pai/2+x)]-asin(x/2)cos(pai-x/ 高一数学已知函数f(x)=cos(2pai-x)cos(pai/2-x)-sin^2x 若sin(pai/6-x)=1/3,则cos(2pai/3+2x)=? f(x)=cos(2x+pai/4)+sin(2x+pai/4)求单调区间