1)-(2m-3)2)n-3(4-2m)3)16a-8(3a+4c)4)t+3分之2(12-9v)5)-(5m+n)-7
几道数学题(去括号)n-3(4-2m)16a-8(3b+4c)t+3分之2(12-9v)-(5m+n)-7(a-3b)-
1.去括号-(2m-3) n-3(4-2m) 16a-8(3b+4c) t+2/3(12-9v) -(5m+n)-7(a
已知2m+n分之m-2n=3,则2m+n分之3(m-2n)+3(2m+n)分之m-2n-4(2m+n)分之5(m-2n)
-(2m-3) n-3(4-2m) 16a-8(3b+4c) t+3分之2(12-9v)
-2(2m-3)2n-(4-2m)16a-3(3b-4c)t-3分之2(24-9v)-(5m+n)-6(a-3b)-2分
(3a^n-2)-6a^n+14a^n-1(因式分解) (m-n)^3+4(n-m)
3分之m+n + 4分之n-m=-4分之1 6分之m+8- 12分之5(n+1)=2
(3m-4n)(4n+3m)-(2m-n)(2m+n)
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
(5m+2n)(5m-2n)-(3m-4n)(4m+3n)
若5m-3n=-4,求出2(m-n)+4(2m-n)
2m-{n+[4m-3(m+2n)]}-5n化简求值