(log2 6)×(log3 6)-(log2 3+log3 2)=
log2(3)+log3(5)+log3(2)=?
log2 3×log3 7=log2 7
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2)
若a=log2 3,b=log3 2,c=log4 6比较大小
lg2+lg5-log2(3)乘log3(2)
log2(20)-log2(5)+2log3(2)×log4(3)
(log3^4+log5^2)(log2^9+log2^根号3)
log2 4=2log3 9=3
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?