cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简
来源:学生作业帮 编辑:搜狗做题网作业帮 分类:数学作业 时间:2024/06/16 23:40:39
cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简
![cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简](/uploads/image/z/18955996-52-6.jpg?t=cos%28%CE%B1%2B5%CF%80%2F12%29cos%28%CE%B1%2B%CF%80%2F6%29%2Bcos%28%CF%80%2F12-%CE%B1%29cos%28%CF%80%2F3-%CE%B1%29+%E5%8C%96%E7%AE%80)
cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α)
=cos(α+5π/12)cos(α+π/6)+cos[π/2-(5π/12+α)]cos[π/2-(π/6+α)]
=cos(α+5π/12)cos(α+π/6)+sin(5π/12+α)sin(π/6+α)
=cos[(α+5π/12)-(α+π/6)]
=cos(5π/12-π/6)
=cos(π/4)
=√2/2
=cos(α+5π/12)cos(α+π/6)+cos[π/2-(5π/12+α)]cos[π/2-(π/6+α)]
=cos(α+5π/12)cos(α+π/6)+sin(5π/12+α)sin(π/6+α)
=cos[(α+5π/12)-(α+π/6)]
=cos(5π/12-π/6)
=cos(π/4)
=√2/2
化简:cos(-π-α)
化简cos平方α+cos平方(α-π/3)+cos平方(α+π/3) 急、~
化简cos(π/12-α)-根号3cos(5π/12+α)
cos(2π/3-α)能等于cosα?
已知cos(α-π6
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a)
【紧急求助】计算:cosα+cos(2π/3 +α)+cos(4π/3 +α)
1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α)
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简cos(π/12)*cos(5π/12)
已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为