一、根号下1+sinX减根号下1-sinX其中X属于
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一、根号下1+sinX减根号下1-sinX其中X属于
二、f(X)=2tanX-(2sin的方*X/2-1)/(sinX/2*cos/2)
三、[1/tan(X/2)-tan(X/2)]*(1+tan的方X)
二、f(X)=2tanX-(2sin的方*X/2-1)/(sinX/2*cos/2)
三、[1/tan(X/2)-tan(X/2)]*(1+tan的方X)
![一、根号下1+sinX减根号下1-sinX其中X属于](/uploads/image/z/19586217-57-7.jpg?t=%E4%B8%80%E3%80%81%E6%A0%B9%E5%8F%B7%E4%B8%8B1%2BsinX%E5%87%8F%E6%A0%B9%E5%8F%B7%E4%B8%8B1-sinX%E5%85%B6%E4%B8%ADX%E5%B1%9E%E4%BA%8E)
①√(1+sinx)-√(1-sinx)
=√[√(1+sinx)-√(1-sinx)]^2
=√[1+sinx+1-sinx-2√(1-sin^2x)]
=√(2-2cosx)
②f(x)=2tanx-[2sin^2(x/2)-1]/(sinx/2*cosx/2)
=2tanx-cosx/(1/2sinx)
=2tanx-2cosx/sinx
=2sinx/cosx-2cosx/sinx
=2[(sin^2x-cos^2x)/sinx*cosx]
=2(-cos2x)/(1/2sin2x)
=-4cot2x
③[1/tan(x/2-tan(x/2]*(1+tan^2x)
=[cos(x/2)/sin(x/2)-sin(x/2)/cos(x/2)]*(1+tan^2x)
=[(cos^2x-sin^2x)/sinxcosx]*(1+tan^2x)
=[cosx/(1/2sinx)]*(1+tan^2x)
=2cotx*(1+tan^2x)
=2cotx+2tanx
=2(cosx/sinx+sinx/cosx)
=2(cos^2x+sin^x)/sinxcosx
=2(cos^2-1/2+sin^2-1/2+1)/(1/2sin2x)
=4(1/2cos2x-1/2cos2x+1)/(sin2x)
=4/sin2x
=√[√(1+sinx)-√(1-sinx)]^2
=√[1+sinx+1-sinx-2√(1-sin^2x)]
=√(2-2cosx)
②f(x)=2tanx-[2sin^2(x/2)-1]/(sinx/2*cosx/2)
=2tanx-cosx/(1/2sinx)
=2tanx-2cosx/sinx
=2sinx/cosx-2cosx/sinx
=2[(sin^2x-cos^2x)/sinx*cosx]
=2(-cos2x)/(1/2sin2x)
=-4cot2x
③[1/tan(x/2-tan(x/2]*(1+tan^2x)
=[cos(x/2)/sin(x/2)-sin(x/2)/cos(x/2)]*(1+tan^2x)
=[(cos^2x-sin^2x)/sinxcosx]*(1+tan^2x)
=[cosx/(1/2sinx)]*(1+tan^2x)
=2cotx*(1+tan^2x)
=2cotx+2tanx
=2(cosx/sinx+sinx/cosx)
=2(cos^2x+sin^x)/sinxcosx
=2(cos^2-1/2+sin^2-1/2+1)/(1/2sin2x)
=4(1/2cos2x-1/2cos2x+1)/(sin2x)
=4/sin2x
{根号下【(1-sinx)/(1+sinx)】-根号下【(1+sinx)/1-sinx】}{根号下【(1-cosx)/(
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