化简系列x方程(x-2)(x-3)+(x-2)(x-3)^2+(x-2)(x-3)+1+(x-2)[(x-3)^2+(x
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化简系列x方程
(x-2)(x-3)+(x-2)(x-3)^2+(x-2)(x-3)+1+(x-2)[(x-3)^2+(x-2)(x-3)(x-4)+(x-3)^2]+(x-2)(x-3)+1 +(x-2)(x-3)^2+(x-2)(x-3)
(x-2)(x-3)+(x-2)(x-3)^2+(x-2)(x-3)+1+(x-2)[(x-3)^2+(x-2)(x-3)(x-4)+(x-3)^2]+(x-2)(x-3)+1 +(x-2)(x-3)^2+(x-2)(x-3)
![化简系列x方程(x-2)(x-3)+(x-2)(x-3)^2+(x-2)(x-3)+1+(x-2)[(x-3)^2+(x](/uploads/image/z/20103304-40-4.jpg?t=%E5%8C%96%E7%AE%80%E7%B3%BB%E5%88%97x%E6%96%B9%E7%A8%8B%EF%BC%88x-2%29%28x-3%29%2B%EF%BC%88x-2%29%28x-3%29%5E2%2B%EF%BC%88x-2%29%28x-3%29%2B1%2B%28x-2%29%5B%28x-3%29%5E2%2B%28x)
原式=(x-2)(x-3){1+(x-3)+1+(x-3)+[(x-3)+(x-2)(x-4)+(x-3)]+1+(x-3)+1]}+2.
=(x-2)(x-3)(x^2-2x)+2.
=x(x-1)(x-2)(x-3)+2
再问: (x^2-2x)+2. 怎么等于x(x-1)+2
再答: x(x-2)+2 (疏忽大意),,犯了不应该犯的错误,对不起。谢谢您指正! 原式=(x(x-2)^2(x-3)+2.
=(x-2)(x-3)(x^2-2x)+2.
=x(x-1)(x-2)(x-3)+2
再问: (x^2-2x)+2. 怎么等于x(x-1)+2
再答: x(x-2)+2 (疏忽大意),,犯了不应该犯的错误,对不起。谢谢您指正! 原式=(x(x-2)^2(x-3)+2.
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