化简(sec^2B-1)(1-csc^2B)+tgBctgB
化简:1/sec^2a+1/csc^2a
化简:secα√(1+tan^2α)+tanα√(csc^2-1)
化简sinθ-cosθ除以(1-tanθ)可得 A -sinθ B -cosθ C -secθ D cscθ
sin^2 a/sec^2-1 +cos^2 a/csc^2-1+cos^acsc^a
1/(1+sin^2a)+1/(1+cos^2a)+1/(1+sec^2a)+1/(1+csc^2)
求证1+tan^2α=sec^2α,1+cot^2α=csc^2α
高数求导法则中 sec^2=1+tan^2 csc^2=1+cot^2 怎么来的
α是锐角,求证tanα﹢cotα﹢secα﹢cscα≥2(√2+1)
锐角A能使下列等式成立:(A)sec^2A+csc^2A=3,(B)tanA+cotA=3/2,(C)sinA+cosA
化简(1+cotα-cscα)(1+tanα+secα)
化简[(secα-cosα)*(cscα-sinα)]/2sinα*cosα
y=sec^2x+csc^2x求导