[1] x/x^2+3x+2 +2/x^2+2x+1+-1/3x+6

来源：学生作业帮编辑：搜狗做题网作业帮分类：数学作业时间：2024/05/12 13:18:01

[1] x/x^2+3x+2 +2/x^2+2x+1+-1/3x+6
[2] 1/a+b-2a-1/a^2-b^2+b/b-a
[3]x/3x-3-2x-1/6(x-1)^2

第一题：原式=x/[(x+1)(x+2)]+2/(x+1)²-1/[3(x+2)]=3x(x+1)/[3(x+1)²(x+2)]+6(x+2)/[3(x+1)²(x+2)]-(x+1)²/[3(x+1)²(x+2)]=(3x²+3x+6x+12-x²-2x-1)/[3(x+1)²(x+2)]=(2x²+7x+11)/[3(x+1)²(x+2)]
第二题：原式=1/(a+b)-b/(a-b)-(2a-1)/(a²-b²)=(a-b-ab-b²)/(a²-b²)-(2a-1)/(a²-b²)=(a-b-ab-b²-2a+1)/(a²-b²)=(1-a-b-ab-b²)/(a²-b²)
第三题：原式=x/[3(x-1)]-(2x-1)/[6(x-1)²]=2x(x-1)/[6(x-1)²]-(2x-1)/[6(x-1)²]=(2x²-2x-2x+1)/[6(x-1)²]=(2x²-4x+1)/[6(x-1)²]

|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) (x+2/x^2-x-6)-(2x/x^2-3x)-(x+1/x^2-6x+9) x+2/x^2-x-6 + 2x/x^3-3x - x+1/x^2-6x+9 1+x+x^2+x^3+.+x^99+x^100 (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 (x-6)×(x-3) (x+2/1)×(x-3/1) 1/(x+3)-(x-2)/(x^2-5x+6) (x+2)(x-3)(x-6)(x-1)=0